【发布时间】:2020-04-18 22:34:48
【问题描述】:
我正在努力在 python3 上创建我的第一个项目。当我使用以下代码时:
def scrape_offers():
r = requests.get("https://www.olx.bg/elektronika/kompyutrni-aksesoari-chasti/aksesoari-chasti/q-1070/?search%5Border%5D=filter_float_price%3Aasc", cookies=all_cookies)
soup = BeautifulSoup(r.text,"html.parser")
offers = soup.find_all("div",{'class':'offer-wrapper'})
for offer in offers:
offer_name = offer.findChildren("a", {'class':'marginright5 link linkWithHash detailsLink'})
print(offer_name.text.strip())
我收到以下错误:
Traceback (most recent call last):
File "scrape_products.py", line 45, in <module>
scrape_offers()
File "scrape_products.py", line 40, in scrape_offers
print(offer_name.text.strip())
File "/usr/local/lib/python3.7/site-packages/bs4/element.py", line 2128, in __getattr__
"ResultSet object has no attribute '%s'. You're probably treating a list of elements like a single element. Did you call find_all() when you meant to call find()?" % key
AttributeError: ResultSet object has no attribute 'text'. You're probably treating a list of elements like a single element. Did you call find_all() when you meant to call find()?
我在 StackOverFlow 上读过很多类似的案例,但我还是忍不住。如果有人有任何想法,请帮助:)
P.S.:如果我在没有 .text 的情况下运行代码,它会显示整个 <a class=...> ... </a>
【问题讨论】:
标签: python html python-3.x text beautifulsoup