【问题标题】:moving-window raster flood fill in R移动窗口光栅洪水填充R
【发布时间】:2017-02-01 17:00:31
【问题描述】:

假设我有一个带有整数值的栅格,将事件的时间描述为一年中的某一天 (DOY)。如果相应年份没有事件,则单元格设置为 NA。 R 'raster' 包的clump() 函数将允许检测具有相同整数值的相邻像元并用唯一ID 标记它们。现在,想象这样的事件(例如火灾)可以随着时间在空间中传播,因此在 DOY 1 上燃烧的单元格 (x, y) 和相邻的单元格(例如 (x+1, y), (x, y+1) ,...) 然后在 DOY 2 上烧毁。因此,我想确定这样的事件,即相邻像素在最多 2 天的 DOY 差异内烧毁(例如 DOY(x,y)=13 和 DOY(x+1 ,y)=15) 并为它们分配一个唯一的 ID:

library(raster)
m<-matrix(c(1,10,11,14,
            2,2,13,NA,
            20,3,25,NA,
            21,25,7,NA), ncol=4, byrow = TRUE)
r<-raster(m) # raster object of matrix

应该产生一个栅格:

res_m<-matrix(c(1,2,2,2,
                1,1,2,NA,
                3,1,4,NA,
                3,4,5, NA), ncol=4, byrow = TRUE)
res_r<-raster(res_m)

或以图形方式:

par(mfrow=c(1,2))
plot(r, xlim=(c(0:1)), main="DOY")
text(r)
plot(res_r, xlim=(c(0:1)), main="classified result")
text(res_r)

plot: initial DOY raster (left) vs. classified result (right)

编辑: 参考 Lorenzo 的评论:事件,其中传播是例如DOY1、DOY2 和 DOY4 应视为一个事件。但是,我无法弄清楚算法会是什么样子,两个不同的事件在传播时会“融化”,但仍会被归类为两个不同的事件。 到目前为止,我解决了效率相当低的问题如下:

#Round 1: find connected components

#cell indices
coli<-rep(1:ncol(r), nrow(r)) 
rowi<-rep(1:ncol(r), each= nrow(r)) 

#neighbourhood matrix (considering only NW, N, NE and W neighbours)
mat_nb <- matrix(c(1,1,1,
                   1,0,NA,
                   NA,NA,NA), nrow=3, ncol=3, byrow = T)

#create ascending class raster
cls<-1:ncell(r)
mcl<-setValues(r, cls)

#create empty raster to fill
ecl<-setValues(r, NA)

#loop through cells
for (j in 1:length(coli)){

  #####get adjacent cells 
  zelle<-cellFromRowCol(r, rowi[j], coli[j])
  nb <- adjacent(r, zelle, directions=mat_nb, pairs=F, sorted=T)

  if(is.na(r[zelle])) {next} # if cell=NA go to next cells
  if(length(nb) == 0) {ecl[zelle] <- mcl[zelle]} # if no neighbours, use ascending class value
  if(length(nb) > 0) {
    if(all(!is.na(r[nb[]]) & r[nb[]] %in% (r[zelle]-2):(r[zelle]+2) & !(unique(ecl[nb[]])))) 
      {ecl[zelle] <- ecl[nb[1]]}  # if all neighbours valid and from same class, assign to class
    if(!is.na(r[nb[1]]) & r[nb[1]] %in% (r[zelle]-2):(r[zelle]+2) & is.na(ecl[zelle])) 
      {ecl[zelle] <- ecl[nb[1]]} # if NW neighbour valid and zelle still unclassified, assign neighbour's class
    if(!is.na(r[nb[2]]) & r[nb[2]] %in% (r[zelle]-2):(r[zelle]+2) & is.na(ecl[zelle])) 
      {ecl[zelle] <- ecl[nb[2]]}  # same for N
    if(!is.na(r[nb[3]]) & r[nb[3]] %in% (r[zelle]-2):(r[zelle]+2) & is.na(ecl[zelle])) 
      {ecl[zelle] <- ecl[nb[3]]}  # same for NE
    if(!is.na(r[nb[4]]) & r[nb[4]] %in% (r[zelle]-2):(r[zelle]+2) & is.na(ecl[zelle])) 
      {ecl[zelle] <- ecl[nb[4]]} # same for W
    if(all(!(r[nb[]] %in% (r[zelle]-2):(r[zelle]+2)))) {ecl[zelle] <- mcl[zelle]} # if all neighbours "invalid", assign scending class value
  }
} # warnings: from pixels with less than 4 nbs

#compare result with initial raster
par(mfrow=c(1,2))
plot(r)
text(r)
plot(ecl)
text(ecl)

在第 2 轮中,连接的组件类被合并。

##Round 2: combine classes

ecla<-ecl #save from first recursion

# only E, SW, S and SE neighbours
mat_agg<-matrix(c(NA,NA,NA,
                  NA,0,1,
                  1,1,1), nrow=3, ncol=3, byrow = T)

for (i in 1:length(coli)){

  #####get adjacent cells 
  zelle<-cellFromRowCol(r, rowi[i], coli[i])
  nb <- adjacent(r, zelle, directions=mat_agg, pairs=F, sorted=T)

  if(is.na(r[zelle])) {next}
  if(length(nb) == 0) {ecl[zelle] <- mcl[zelle]}
  if(length(nb) > 0) {
    if(r[nb[2]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] < ecla[nb[2]]) {ecla[nb[2]] <- ecla[zelle]}
    if(r[nb[2]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] > ecla[nb[2]]) {ecla[zelle] <- ecla[nb[2]]}
    if(r[nb[3]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] < ecla[nb[3]]) {ecla[nb[3]] <- ecla[zelle]}
    if(r[nb[3]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] > ecla[nb[3]]) {ecla[zelle] <- ecla[nb[3]]}
    if(r[nb[4]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] < ecla[nb[4]]) {ecla[nb[4]] <- ecla[zelle]}
    if(r[nb[4]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] > ecla[nb[4]]) {ecla[zelle] <- ecla[nb[4]]}
    if(r[nb[1]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] < ecla[nb[1]]) {ecla[nb[1]] <- ecla[zelle]}
    if(r[nb[1]] %in% (r[zelle]-2):(r[zelle]+2) & ecla[zelle] > ecla[nb[1]]) {ecla[zelle] <- ecla[nb[1]]}
  } # warnings: from pixels with less than 4 nbs
}

# plot results
par(mfrow=c(1,3))
plot(ecl) # round 1 result
text(ecl)
plot(r)
text(r)
plot(ecla) # round 2 result
text(ecla)

【问题讨论】:

  • 棘手的问题......但是,您应该更好地定义集群应该如何“传播”。我的意思是:您说“我想确定这样的事件,其中相邻像素在 DOY 最大差异为 2 天之内燃烧”,但是如果您在 doy 1 中有一个单元格被烧毁,与一个单元格 = 2 相邻,它本身相邻到带有 doy 4 的单元格:即使与它的“距离”超过 2 天,最后一个单元格是否属于同一单元格 1 集群?如果您从同一个 DOY 开始有不同且分开的“烧毁区域”怎么办?他们使用相同的身份证还是不同的身份证?
  • 请问你是如何定义相邻的?皇后案(8向)?车的(4方向)?
  • 另外,您的迭代是否从最低 DOY 开始?因为这可能会影响传播方式
  • 如果更新了我的问题并添加了我到目前为止的进度。我想考虑一个 8 方向的社区。此外,我使用了从左上角单元格开始的单元格实现。

标签: raster fill image-segmentation r-raster connected-components


【解决方案1】:

这是一个棘手的老问题。我放弃了将复杂的函数传递给 raster::focal ,所以我改为使用 data.table 进行处理并使用了一系列规则。可能有更简单的方法可以做到这一点,但无论如何。

这适用于您的数据和我生成的 6x6 栅格。请测试一下,看看效果如何;

# packages
library(raster)
library(data.table)

# your example data
m<-matrix(c(1,10,11,14,
            2,2,13,NA,
            20,3,25,NA,
            21,25,7,NA), ncol=4, byrow = TRUE)
r<-raster(m)

# convert raster to data.table, add cell number attribute, and zonal ID column 
# and columns for the queen's case relationships (these columns contain the cell ID 
# that holds that relationship)
df <- as.data.table(as.data.frame(r))
df[,CELL:=as.numeric(row.names(df))]
df[,ID:=0]
df[,c("TL","T","TR","R","BR","B","BL","L") := 
   list(CELL-(ncol(r)+1),CELL-ncol(r),CELL-(ncol(r)-1),
   CELL+1,CELL+(ncol(r)+1),CELL+ncol(r),CELL+(ncol(r)-1),CELL-1)]

# set appropriate queen's case relations to NA for all edge cells
df[c(CELL %in% seq(1,ncell(r),ncol(r))), c("TL","L","BL")] <- NA
df[c(CELL %in% seq(ncol(r),ncell(r),ncol(r))), c("TR","R","BR")] <- NA
df[c(CELL %in% 1:ncol(r)), c("TL","T","TR")] <- NA
df[c(CELL %in% (ncell(r)-nrow(r)+1):ncell(r)), c("BL","B","BR")] <- NA

# melt data table, add the cell values that correspond to each relationship,
# remove rows that wont be needed just now
dfm <- melt(df,id.vars=c("layer","CELL","ID"))
dfm[,NEIGH.VAL := r[dfm[,value]]]
dfm[,WITHIN2:=ifelse(abs(layer-NEIGH.VAL)>2,F,T)]
dfm <- dfm[!is.na(value)&!is.na(layer)&!is.na(NEIGH.VAL)][order(CELL)]
dfm <- dfm[WITHIN2==TRUE]
dfm[,NEIGH.ID := 0]

# this is a tricky loop and any errors that may occur are more than likely produced here.
# It starts at the lowest cell ID with a value and builds a lookup up vector of cell IDs
# that conform to the DOY being within 2 days, then sets the ID for them all.
# It then moves on to the next cell ID available that has not had a zone ID assigned
# and does the same thing, with a zonal ID one higher. etc.
for(n in unique(dfm[,CELL])){
   while(nrow(dfm[CELL==n & NEIGH.ID==0]) > 0){
    lookups <- unique(dfm[CELL==n,value])
    while(all(unique(dfm[CELL %in% lookups,value]) == lookups)==F){
      lookups <- unique(c(lookups,dfm[CELL %in% lookups,value]))
      lookups <- unique(dfm[CELL %in% lookups,value])}
   dfm[CELL %in% lookups, NEIGH.ID := max(dfm[,NEIGH.ID])+1]
   }
}

# this section creates a raster of 1:ncell of the original data and assigns a zonal ID
# with reclassify. Everything that did not get a zonal ID (single 'island' cells
# and original NA cells) becomes NA
results <- unique(dfm[,list(CELL,NEIGH.ID)])
rzone <- r
rzone[] <- 1:ncell(rzone)
rc <- reclassify(rzone, results)
rc[!(rzone %in% results[[1]])] <- NA

# Now we need to determine those single 'island' cells and reinstate them, with their
# own ID, increasing incrementally from the highest extant ID based on the above analysis
final.vec <- which(!(rzone[] %in% results[[1]]) & !(rzone[] %in% which(is.na(values(r)))))

rc[final.vec] <- seq((cellStats(rc,max)+1),(cellStats(rc,max)+length(rc[final.vec])),1)

# plot to check
par(mfrow=c(1,3))
plot(r, xlim=(c(0:1)), main="DOY")
text(r)
plot(res_r, xlim=(c(0:1)), main="DOY")
text(res_r)
plot(rc, xlim=(c(0:1)), main="zones result")
text(rc)

这段代码也适用于下面的代码,不过可以试试看,祈祷吧! (忽略警告);

m<-matrix(c(1,3,5,14,NA,21,
            2,2,17,NA,23,25,
            9,15,4,5,9,NA,
            14,11,14,21,25,7,
            NA,NA,16,2,4,6,
            NA,17,25,15,1,NA), ncol=6, byrow = TRUE)
r<-raster(m) # raster object of matrix

【讨论】:

  • 像魅力一样工作 - 处理效率随着您的方法而大大提高。谢谢!使用导入的栅格对象(例如 .tif)时,在开头设置 names(rasterobj) &lt;- "layer" 可以避免“棘手循环”中的麻烦。
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