【发布时间】:2015-05-27 12:41:07
【问题描述】:
我创建了一个用户注册和登录应用。我做了以下事情。
MainActivity.java
si=(Button)findViewById(R.id.button);
su=(Button)findViewById(R.id.button2);
si.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent intent1=new Intent(MainActivity.this,Login.class);
startActivity(intent1);
}
});
su.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent intent2=new Intent(MainActivity.this,Signup.class);
startActivity(intent2);
}
});
Signup.java
databaseAdapter=new DatabaseAdapter(this);
databaseAdapter=databaseAdapter.open();
un=(EditText)findViewById(R.id.editText);
pwd=(EditText)findViewById(R.id.editText2);
cnfpwd=(EditText)findViewById(R.id.editText3);
signu=(Button)findViewById(R.id.button3);
signu.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String Uname=un.getText().toString();
String passw=pwd.getText().toString();
String cnfpassw=cnfpwd.getText().toString();
if (Uname.equals("")||passw.equals("")||cnfpassw.equals("")){
//Toast.makeText(getApplicationContext(),"Please Fill all the Fields",Toast.LENGTH_SHORT).show();
show("Error","Please fill all the fields");
return;
}
if(!passw.equals(cnfpassw)){
//Toast.makeText(getApplicationContext(),"Password does not match",Toast.LENGTH_SHORT).show();
show("Error","Password does not match");
pwd.setText("");
cnfpwd.setText("");
return;
} else {
databaseAdapter.insertEntry(Uname,passw);
//Toast.makeText(getApplicationContext(),"Account Created Successfully",Toast.LENGTH_LONG).show();
show("Success", "Account Created Successfully");
//finish();
un.setText("");
pwd.setText("");
cnfpwd.setText("");
}
}
});
}
private void show(String title, String message) {
AlertDialog.Builder builder=new AlertDialog.Builder(Signup.this);
builder.setCancelable(true);
builder.setTitle(title);
builder.setMessage(message);
builder.show();
}
Login.java
databaseAdapter=new DatabaseAdapter(this);
databaseAdapter=databaseAdapter.open();
UN=(EditText)findViewById(R.id.editText4);
PWD=(EditText)findViewById(R.id.editText5);
si=(Button)findViewById(R.id.button4);
si.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String UserName=UN.getText().toString();
String Password=PWD.getText().toString();
String storedPassword=databaseAdapter.getSingleEntry(UserName);
//String storesUserName=databaseAdapter.getUserName(Password);
if (UserName.equals("")||Password.equals("")){
show("Error","Please fill all Fields");
return;
}
if (Password.equals(storedPassword)){
//Toast.makeText(Login.this,"Login Successful",Toast.LENGTH_SHORT).show();
show("Success","Login Successful");
String storedUserName=databaseAdapter.getUserDetails(Password);
Toast.makeText(getApplicationContext(),storedUserName,Toast.LENGTH_SHORT).show();
Bundle bundle=new Bundle();
bundle.putString("number",storedUserName);
Intent intent2=new Intent(Login.this,Inbox.class);
intent2.putExtras(bundle);
startActivity(intent2);
} else {
//Toast.makeText(getApplicationContext(),"Username or Password is incorrect",Toast.LENGTH_SHORT).show();
show("Error","Username or Password is incorrect");
UN.setText("");
PWD.setText("");
}
}
});
}
private void show(String title, String message) {
AlertDialog.Builder builder=new AlertDialog.Builder(Login.this);
builder.setCancelable(true);
builder.setTitle(title);
builder.setMessage(message);
builder.show();
}
现在我可以从数据库注册和登录。但是Database 允许冗余。即,它允许相同的值任意多次。我想避免这种情况,以便注册唯一的用户名。有什么解决办法吗?
【问题讨论】:
-
在插入数据库之前检查值是否存在
-
检查的条件是什么?请。我不知道。
-
这不是冗余而是唯一性。
-
为您的用户名+密码列组合添加唯一约束
-
是的,谢谢
标签: android database sqlite redundancy