代码执行中的小问题，python纸牌游戏模拟

Question

这可能与谁有关，

这是纸牌游戏模拟的一些代码。 （战争游戏）。当我运行它时，我收到此错误：

player0.append(player1[range(warcard1 + 1)] 
      ^
SyntaxError: invalid syntax

我不知道错误是什么，但也许这里有人知道。希望有人可以为我解决这个问题。当然，代码仍在进行中，所以如果有任何其他错误，我很乐意听到它们及其可能的解决方案。

import random

cards = ['ace', 'ace', 'ace', 'ace', '1', '1', '1', '1', '2', '2', '2', '2', '3', '3', '3', '3', '4', '4', '4', '4', '5', '5', '5', '5', '6', '6', '6', '6', '7', '7', '7', '7', '8', '8', '8', '8', '9', '9', '9', '9', '10', '10', '10', '10', 'jack', 'jack', 'jack', 'jack', 'queen', 'queen', 'queen', 'queen', 'king', 'king', 'king', 'king']

order = ['ace', '1', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'jack', 'queen', 'king'] 

print "shuffling cards" 
random.shuffle(cards,random.random)
print "lets play"
player0 = [cards[i] for i in range(len(cards)) if i % 2 == 1]

player1 = [cards[i] for i in range(len(cards)) if i % 2 == 0]

while (len(player0) > 0 or len(player1) > 0):

    nextcard0 = player0[0]
    nextcard1 = player1[0]

    cardplayed0 = order.index(nextcard0)

    cardplayed1 = order.index(nextcard1)

    if cardplayed0 > cardplayed1:

        player0.append(nextcard0)
        player0.append(nextcard1)
        player0.remove(nextcard0)
        player1.remove(nextcard1)

    elif cardplayed0 < cardplayed1:

        player1.append(nextcard1)
        player1.append(nextcard0)
        player1.remove(nextcard1)
        player0.remove(nextcard0)

    elif cardplayed0 == cardplayed1:
        while warcardvalue0 == warcardvalue1:
            if len(player0) >= 4:
                warcard0 = 4
            elif len(player0) < 4:
                warcard0 = len(player0)

            if len(player1) >= 4:
                warcard1 = 4
            elif len(player1) < 4:
                warcard1 = len(player1)


            warcardvalue0 = order.index(warcard0)
            warcardvalue1 = order.index(warcard1)

            if warcardvalue0 > warcardvalue1:
                player0.append(player0[range(warcard0 + 1)]
                player0.append(player1[range(warcard1 + 1)] 
                player0.remove(player0[range(warcard0 + 1)]
                player1.remove(player1[range(warcard1 + 1)] 

            elif warcardvalue0 < warcardvalue1:
                player1.append(player1[range(warcard1 + 1)]
                player1.append(player0[range(warcard0 + 1)] 
                player1.remove(player1[range(warcard1 + 1)]
                player0.remove(player0[range(warcard0 + 1)] 
            else
                print "another war!" 


if len(player1) == 0:
    print "player1 won!"
elif len(player0) == 0:
    print "player0 won!"

Answer 1

错误信息中指示的行

player0.append(player1[range(warcard1 + 1)] 
                                           ^

缺少结束)

事实上，所有这些行都缺少右括号：

       if warcardvalue0 > warcardvalue1:
            player0.append(player0[range(warcard0 + 1)]
            player0.append(player1[range(warcard1 + 1)] 
            player0.remove(player0[range(warcard0 + 1)]
            player1.remove(player1[range(warcard1 + 1)] 

        elif warcardvalue0 < warcardvalue1:
            player1.append(player1[range(warcard1 + 1)]
            player1.append(player0[range(warcard0 + 1)] 
            player1.remove(player1[range(warcard1 + 1)]
            player0.remove(player0[range(warcard0 + 1)] 

您可能需要查看您的代码以确保没有其他此问题的实例。

另外，您可能会考虑（并且肯定会受益于）为您执行paren matching 的编辑器，并会提醒您注意类似的问题。我用了一个，绝对值得。

如果您对此类编辑器感兴趣，可以从这里开始探索选项：Top 10 Best Text Editors With Brace Matching

Answer 2

您在每个 append/remove 行上都缺少右括号。