【问题标题】:tic tac toe vhdl student projecttic tac toe vhdl 学生项目
【发布时间】:2019-04-14 14:48:12
【问题描述】:

问题是输出与 ifs 不匹配。我想要,例如行 A,如果一切都是 1,则输出应该是 11。但它不是

library ieee;  
 use ieee.std_logic_1164.all;  
 use ieee.numeric_std.all;  

 entity galo_ports is  
  port( LinA : in unsigned(2 downto 0); 
    LinB : in unsigned(2 downto 0);
    LinC : in unsigned(2 downto 0);

    output : out unsigned(1 downto 0)); 
 end galo_ports;

ARCHITECTURE main OF galo_ports IS
SIGNAL values: std_logic_vector(1 downto 0);
SIGNAL condition1A: boolean;
SIGNAL condition2A: boolean;
SIGNAL condition3A: boolean;
SIGNAL condition1B: boolean;
SIGNAL condition2B: boolean;
SIGNAL condition3B: boolean;
SIGNAL condition1C: boolean;
SIGNAL condition2C: boolean;
SIGNAL condition3C: boolean;
SIGNAL condition1COL1: boolean;
SIGNAL condition2COL1: boolean;
SIGNAL condition3COL1: boolean;
SIGNAL condition1COL2: boolean;
SIGNAL condition2COL2: boolean;
SIGNAL condition3COL2: boolean;
SIGNAL condition1COL3: boolean;
SIGNAL condition2COL3: boolean;
SIGNAL condition3COL3: boolean;
SIGNAL condition1DIG1: boolean;
SIGNAL condition2DIG1: boolean;
SIGNAL condition3DIG1: boolean;
SIGNAL condition1DIG2: boolean;
SIGNAL condition2DIG2: boolean;
SIGNAL condition3DIG2: boolean;
BEGIN
values <= "10";

--CONDIÇÃOES:
--LINHA 1
condition1A <= LinA(0) = LinA(1) and LinA(1) = LinA(2);
condition2A <= LinA(0) = values(0) or LinA(0) = values(1);
condition3A <= LinA(0) = values(1);
--LINHA 2
condition1B <= LinB(0) = LinB(1) and LinB(1) = LinB(2);
condition2B <= LinB(0) = values(0) or LinB(0) = values(1);
condition3B <= LinB(0) = values(1);
--LINHA 3
condition1C <= LinC(0) = LinC(1) and LinC(1) = LinC(2);
condition2C <= LinC(0) = values(0) or LinC(0) = values(1);
condition3C <= LinC(0) = values(1);
--COLUNA 1
condition1COL1 <= LinA(0) = LinB(0) and LinB(0) = LinC(0);
condition2COL1 <= LinA(0) = values(0) or LinA(0) = values(1);
condition3COL1 <= LinA(0) = values(1);
--COLUNA 2
condition1COL2 <= LinA(1) = LinB(1) and LinB(1) = LinC(1);
condition2COL2 <= LinA(1) = values(0) or LinA(1) = values(1);
condition3COL2 <= LinA(1) = values(1);
--COLUNA 3
condition1COL3 <= LinA(2) = LinB(2) and LinB(2) = LinC(2);
condition2COL3 <= LinB(2) = values(0) or LinA(2) = values(1);
condition3COL3 <= LinB(2) = values(1);
--DIAGONAL 1
condition1DIG1 <= LinA(0) = LinB(1) and LinB(1) = LinC(2);
condition2DIG1 <= LinA(0) = values(0) or LinA(0) = values(1);
condition3DIG1 <= LinA(0) = values(1);
--DIAGONAL 2
condition1DIG2 <= LinA(2) = LinB(1) and LinB(1) = LinC(0);
condition2DIG2 <= LinA(2) = values(0) or LinA(2) = values(1);
condition3DIG2 <= LinA(2) = values(1);
    PROCESS(LinA, LinB, LinC)
    BEGIN
        --LINHA 1
        IF condition1A=TRUE and condition2A=TRUE and condition3A=TRUE THEN output <= "11";
        END IF;
        --LINHA 2
        IF (condition1B) and (condition2B) and (condition3B) THEN output <= "11"; ELSE output <="00";
        END IF;
        --LINHA 3
        IF condition1C and condition2C and condition3C THEN output <= "11";
        END IF;
        --COLUNA 1
        IF condition1COL1 and condition2COL1 and condition3COL1 THEN output <= "11";
        END IF;
        --COLUNA 2
        IF condition1COL2 and condition2COL2 and condition3COL2 THEN output <= "11";
        END IF;
        --COLUNA 3
        IF condition1COL3 and condition2COL3 and condition3COL3 THEN output <= "11";
        END IF;
        --DIAGONAL 1
        IF condition1DIG1 and condition2DIG1 and condition3DIG1 THEN output <= "11";
        END IF;
        --DIAGONAL 2
        IF condition1DIG2 and condition2DIG2 and condition3DIG2 THEN output <= "11";
        END IF;

    END PROCESS;
END main;

游戏包含一个 9 个位置的棋盘,每个玩家在一个免费的房子里移动,并用“0”(玩家 A)或“1”(玩家 B)标记它。

胜利将授予能够在水平、垂直或对角线上放置 3 个“0”或 3 个“1”的玩家。

解决方案应在退出时显示哪个玩家获胜或平局 - 如果没有玩家能够实现定义的目标。

【问题讨论】:

    标签: vhdl


    【解决方案1】:

    我删除了我原来的答案,因为@pm101 指出它完全偏离了轨道。

    编译您的设计后,警告说明了明显的原因:

    galo_ports.vhd(142) 处的 VHDL Process Statement 警告:信号 “condition1A”在 Process Statement 中读取,但不在 流程声明的敏感度列表

    linAlinBlinC 更改时,conditionXXX 信号的值会更新。但是,该过程是同时执行的,并且这些条件信号的值尚未更新。如果您正在模拟设计,您会看到output 的值滞后:它会在输入更改时更新,但它可能会显示之前输入的游戏结果。

    修复过程敏感度列表以包含所有条件信号。然后,当您的conditionXXX 信号发生变化并且条件表达式被正确评估时,该过程将被执行。所以像:

    PROCESS(condition1A, condition2A, condition3A, condition1B, condition2B, condition3B, condition1C, condition2C, condition3C, condition1COl1, condition2COL1, condition3COL1, condition1COL2, condition2COL2, condition3COL2, condition1COL3, condition2COL3, condition3COL3, condition1DIG1, condition2DIG1, condition3DIG1, condition1DIG2, condition2DIG2, condition3DIG2)
    

    此外,我会将该条件列表包装到一个带有ELSIF 语句的IF 块中。然后在ELSE 语句中,您还必须定义output 在没有获胜者时的值(或0 是获胜者):

      --LINHA 1
      IF condition1A=TRUE and condition2A=TRUE and condition3A=TRUE THEN output <= "11";
      --LINHA 2
      ELSIF (condition1B) and (condition2B) and (condition3B) THEN output <= "11";
      --LINHA 3
      ELSIF condition1C and condition2C and condition3C THEN output <= "11";
      --COLUNA 1
      ELSIF condition1COL1 and condition2COL1 and condition3COL1 THEN output <= "11";
      --COLUNA 2
      ELSIF condition1COL2 and condition2COL2 and condition3COL2 THEN output <= "11";
      --COLUNA 3
      ELSIF condition1COL3 and condition2COL3 and condition3COL3 THEN output <= "11";
      --DIAGONAL 1
      ELSIF condition1DIG1 and condition2DIG1 and condition3DIG1 THEN output <= "11";
      --DIAGONAL 2
      ELSIF condition1DIG2 and condition2DIG2 and condition3DIG2 THEN output <= "11";
      ELSE output <= "00"; -- 0 wins or no winner. 
      END IF;
    

    【讨论】:

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