基于变量运行定义序列，并使用来自另一个变量的附加条件

Question

structure(list(group = c(NA, "A", "B", NA, "B", "B", "B", "B", 
"B", "B", "B", "B", "B", "B", "B", "B", "B", "B", "B", "B", "B", 
"B", NA, NA, "B", "B", "A", "A", NA, NA, "B", "B", "B", NA, "A", 
"A", "A", "A", "A", "A", "A", "A", "A", "A", NA, NA, "B", "B", 
NA, "A"), seq_break = c(TRUE, FALSE, FALSE, TRUE, FALSE, FALSE, 
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, 
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, 
TRUE, TRUE, FALSE, FALSE, TRUE, TRUE, FALSE, FALSE, FALSE, TRUE, 
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, 
FALSE, TRUE, TRUE, FALSE, FALSE, TRUE, FALSE)), .Names = c("group", 
"seq_break"), class = c("tbl_df", "tbl", "data.frame"), row.names = c(NA, 
-50L))

在上面的数据中，我需要定义一个包含group 列的运行长度类型ID 的列（如data.table::rleid 产生，但忽略NA）。正如你所看到的，我们还有seq_break 列，它应该结束一个序列。它通常会这样做，例如group = NA 然后seq_break = TRUE。但有时seq_break = TRUE 和组是A 或B - 那么即使下一行指的是同一个组，也应该结束序列并开始新的序列。因此，例如对于行25:26，我们应该有两个不同的序列ID，即使两个事件都指向组B。一般来说，预期的输出如下所示：

structure(list(group = c(NA, "A", "B", NA, "B", "B", "B", "B", 
"B", "B", "B", "B", "B", "B", "B", "B", "B", "B", "B", "B", "B", 
"B", NA, NA, "B", "B", "A", "A", NA, NA, "B", "B", "B", NA, "A", 
"A", "A", "A", "A", "A", "A", "A", "A", "A", NA, NA, "B", "B", 
NA, "A"), seq_break = c(TRUE, FALSE, FALSE, TRUE, FALSE, FALSE, 
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, 
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, 
TRUE, TRUE, FALSE, FALSE, TRUE, TRUE, FALSE, FALSE, FALSE, TRUE, 
FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, 
FALSE, TRUE, TRUE, FALSE, FALSE, TRUE, FALSE), expected_output = c(NA, 
1, 2, NA, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 
3, NA, NA, 4, 5, 6, 6, NA, NA, 7, 7, 7, NA, 8, 8, 8, 8, 8, 8, 
8, 8, 8, 8, NA, NA, 11, 11, NA, 12)), .Names = c("group", "seq_break", 
"expected_output"), class = c("tbl_df", "tbl", "data.frame"), row.names = c(NA, 
-50L))

如何使用tidyverse 实现这一目标？

Answer 1

使用tidyverse 和data.table 的解决方案。假设 dt1 是您的示例数据框，dt3 是最终输出。请注意，我认为在预期输出中，第 47 到 48 行应该是 9，第 50 行应该是 10。我不确定为什么在你的预期输出中第 47 到 48 行是 11，而第 50 行是 12。

library(tidyverse)
library(data.table)

dt2 <- dt1 %>% rowid_to_column() 

dt3 <- dt2 %>%
  mutate(ID = rleid(group, seq_break)) %>%
  group_by(group, seq_break, ID) %>%
  filter(!(is.na(group) & seq_break & row_number() > 1)) %>%
  ungroup() %>%
  mutate(ID2 = cumsum(seq_break)) %>%
  drop_na(group) %>%
  mutate(expected_output = rleid(group, ID2)) %>%
  select(rowid, expected_output) %>%
  left_join(dt2, ., by = "rowid") %>%
  select(-rowid)

dt3
# # A tibble: 50 x 3
#    group seq_break expected_output
#    <chr> <lgl>               <int>
#  1 NA    TRUE                   NA
#  2 A     FALSE                   1
#  3 B     FALSE                   2
#  4 NA    TRUE                   NA
#  5 B     FALSE                   3
#  6 B     FALSE                   3
#  7 B     FALSE                   3
#  8 B     FALSE                   3
#  9 B     FALSE                   3
# 10 B     FALSE                   3
# # ... with 40 more rows