【发布时间】:2012-07-24 12:18:41
【问题描述】:
我有 data.frame :
df1<-data.frame("Sp1"=1:6,"Sp2"=7:12,"Sp3"=13:18)
rownames(df1)=c("A","B","C","D","E","F")
df1
Sp1 Sp2 Sp3
A 1 7 13
B 2 8 14
C 3 9 15
D 4 10 16
E 5 11 17
F 6 12 18
我通过 rowSums(df1) 的截止值过滤 df1 并返回我想包含在下游分析中的站点(行名)。
include<-rownames(df1[rowSums(df1)>=22,])
include
[1] "B" "C" "D" "E" "F"
我有第二个 data.frame :
df2<-data.frame(site.x=c("A","B","C"), site.y=c("D","E","F"),score=1:3)
site.x site.y score
1 A D 1
2 B E 2
3 C F 3
我想过滤 df2 使其仅包含 df2$site.x 和 df2$site.y 与“包含”中列出的站点完全相同的行,即过滤掉包含“A”的行并返回。
site.x site.y score
2 B E 2
3 C F 3
我试过了:
filter<-df2$site.x == include & df2$site.y == include
filtered<-df2[filter,]
感谢您的建议!
回答
使用 %in%
filter<-df2$site.x %in% include & df2$site.y =%in% include
filtered<-df2[filter,]
filtered
site.x site.y score
2 B E 2
3 C F 3
【问题讨论】:
-
可能用
%in%代替== -
没有骰子!您认为这与“包含”的结构有关吗?