【发布时间】:2018-03-06 02:41:21
【问题描述】:
Q1.有没有更直接(但仍然是tidyverse)的方法来创建这样的汇总表?
library(tidyverse)
library(knitr)
library(kableExtra)
df <- data.frame(group=c(1, 1, 1, 1, 0, 0, 0, 0),
v1=c(1, 2, 3, 4, 5, 6, 1, 2),
v2=c(4, 3, 2, 5, 3, 5, 3, 8),
v3=c(0, 1, 0, 1, 1, 0, 1, 1))
df %>%
group_by(group) %>%
summarise(v1=paste0(round(mean(v1), 2),
" (",
round(sd(v1), 2),
")"),
v2=paste0(round(mean(v2), 2),
" (",
round(sd(v2), 2),
")"),
v3=round(mean(v3)*100, 1)
) %>%
dplyr::select(-group) %>%
t() %>%
`rownames<-` (c("v1 mean (SD)",
"v2 mean (SD)",
"Percent v3")) %>%
kable("html",
col.names=c("Group 0", "Group 1")) %>%
kable_styling()
Q2.与此相关,有没有办法在不重复summarise代码的情况下将summarise的两个级别(例如,不分组+分组)结合起来?
all <-
df %>%
summarise(v1=paste0(round(mean(v1), 2),
" (",
round(sd(v1), 2),
")"),
v2=paste0(round(mean(v2), 2),
" (",
round(sd(v2), 2),
")"),
v3=round(mean(v3)*100, 1)
) %>%
t() %>%
`rownames<-` (c("v1 mean (SD)",
"v2 mean (SD)",
"Percent v3"))
groups <-
df %>%
group_by(group) %>%
summarise(v1=paste0(round(mean(v1), 2),
" (",
round(sd(v1), 2),
")"),
v2=paste0(round(mean(v2), 2),
" (",
round(sd(v2), 2),
")"),
v3=round(mean(v3)*100, 1)
) %>%
dplyr::select(-group) %>%
t() %>%
`rownames<-` (c("v1 mean (SD)",
"v2 mean (SD)",
"Percent v3"))
all %>%
cbind(groups) %>%
kable("html",
col.names=c("All", "Group 0", "Group 1")) %>%
kable_styling()
【问题讨论】:
-
我不确定你在问什么。您显示的代码有什么问题?
-
就其工作而言没有任何问题,但特别是 Q2 的解决方案似乎效率低下,因为我定义了两次
summarise()。