【发布时间】:2018-08-06 03:27:02
【问题描述】:
我的数据是:
try<-data.frame(Gender=c("Male","Male","Female","Male","Female","Male","Female","Female","Male","Male", "Female","Male","Male","Male", "Male"),
Est=c(0.9956, 1.035, 2.0731, 0.0824, 3.0987, 5.0982, 6.0707, 5.0393, 2.7046, 4.0783, 0, 2.0923, 4.2348, 1.9561, 6.9262))
我需要再添加一列来将 Est 值重新编码为:
Gender Est X
1 Male 0.9956 0
2 Male 1.0350 1
3 Female 2.0731 2
4 Male 0.9824 0
5 Female 3.0987 3
6 Male 5.0982 5
7 Female 6.0707 6
8 Female 5.0393 5
9 Male 2.7046 2
10 Male 4.0783 4
11 Female 0.0000 0
12 Male 2.0923 2
13 Male 4.2348 4
14 Male 1.9561 1
15 Male 6.9262 6
其中 (0,1]=0, (1,2]=1, (2,3]=2, (3,4]=3, (4,5]=4, (5,6]= 5, (6,7]=6.
【问题讨论】:
-
try$X <- floor(try$Est) -
您可以按照上面的建议使用
floor或使用trunc -
如果我想更改间隔并尝试使其更具动态性,有什么建议吗?例如,如果我使用区间 (0,2]=0, (2,4]=2, (4,6]=4 或 (0,3]=0, (3,6]=3
-
在这种情况下,您可以使用我的代码并将中断和标签中的新间隔指定为:
try$X = cut(x = try$Est,breaks = c(0,2,4,6),labels = c(0,2,4),right = TRUE,include.lowest = TRUE)` -
使用数学 (
floor(try$Est / 2) * 2) 或cut,但请注意,后者会返回一个您希望使用as.numeric(as.character(cut(try$Est, ...)))强制返回为数字的因子