在文本中搜索关键字之前截断内容

Question

我使用下面的代码在我的文本中的第一个搜索关键字之前和之后截断我的内容（这是我的搜索页面），除了在截断开头将单词切成两半的代码之外，一切正常，它不会在截断末尾截断单词。

例子：

lients at the centre of the relationship and to offer a first class service to them, which includes tax planning, investment management and estate planning. We believe that our customer focused and...

（编辑：有时单词中缺少一个以上的字符）

您会看到它已经从“clients”中删除了“c”。它只发生在文本的开头而不是结尾。我怎样才能解决这个问题？我相信我已经成功了一半。到目前为止的代码：

function neatest_trim($content, $chars, $searchquery,$characters_before,$characters_after) {
            if (strlen($content) > $chars) {
                 $pos = strpos($content, $searchquery);
                 $start = $characters_before < $pos ? $pos - $characters_before : 0;
                $len = $pos + strlen($searchquery) + $characters_after - $start;
                $content = str_replace('&nbsp;', ' ', $content);
                $content = str_replace("\n", '', $content);
                $content = strip_tags(trim($content));
                $content = preg_replace('/\s+?(\S+)?$/', '', mb_substr($content, $start, $len));
                $content = trim($content) . '...';
                $content = strip_tags($content);
                $content = str_ireplace($searchquery, '<span class="highlight" style="background: #E6E6E6;">' . $searchquery . '</span>', $content);
            }
            return $content;
        }



 $results[] = Array(
  'text' => neatest_trim($row->content,200,$searchquery,120,80)
            );

Answer 1

您在开始时保留的 120 个字符不检查第 120 个字符是空格还是字母，无论如何都只是剪切那里的字符串。

我会进行此更改，以搜索距我们开始位置最近的“空间”。

$start = $characters_before < $pos ? $pos - $characters_before : 0;
// add this line:
$start = strpos($content, ' ', $start);
$len = $pos + strlen($searchquery) + $characters_after - $start;

这样$start 是空格的位置，而不是单词中的字母。

你的函数会变成：

function neatest_trim($content, $chars, $searchquery,$characters_before,$characters_after) {
    if (strlen($content) > $chars) {
    $pos = strpos($content, $searchquery);
    $start = $characters_before < $pos ? $pos - $characters_before : 0;
    $start = strpos($content, " ", $start);
    $len = $pos + strlen($searchquery) + $characters_after - $start;
    $content = str_replace('&nbsp;', ' ', $content);
    $content = str_replace("\n", '', $content);
    $content = strip_tags(trim($content));
    $content = preg_replace('/\s+?(\S+)?$/', '', mb_substr($content, $start, $len));
    $content = trim($content) . '...';
    $content = strip_tags($content);
    $content = str_ireplace($searchquery, '<span class="highlight" style="background: #E6E6E6;">' . $searchquery . '</span>', $content);
    }
    return $content;
  }

Answer 2

为什么不使用替换正则表达式？

$result = preg_replace('/.*(.{10}\bword\b.{10}).*/s', '$1', $subject);

所以这将修剪关键字 'word'

前后 10 个字符的所有内容

解释：

# .*(.{10}\bword\b.{10}).*
# 
# Options: dot matches newline
# 
# Match any single character «.*»
#    Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
# Match the regular expression below and capture its match into backreference number 1 «(.{10}\bword\b.{10})»
#    Match any single character «.{10}»
#       Exactly 10 times «{10}»
#    Assert position at a word boundary «\b»
#    Match the characters “word” literally «word»
#    Assert position at a word boundary «\b»
#    Match any single character «.{10}»
#       Exactly 10 times «{10}»
# Match any single character «.*»
#    Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»

所以这个正则表达式的作用是查找您指定的单词（并且仅查找该单词，因为它包含在 \b - 单词边界中）并且它还查找 ant 将单词之前的 10 个字符存储（包括该单词）为以及它后面的十个字符。您可以自己构造正则表达式，其中包含前后字符的变量，当然还有关键字。正则表达式也匹配其他所有内容，但替换只使用反向引用 $1，这是您想要的输出。