【发布时间】:2020-11-25 13:44:40
【问题描述】:
如果我在没有管道工功能的情况下运行我的代码,弹出图确实可以正常工作。但如果我使用管道工功能运行,我会收到错误 404 的 web。 知道如何解决这个问题吗? popupgraph 与水管工 api 一起工作?
library(dplyr)
library(ggplot2)
library(plotly)
library(leaflet)
library(htmltools)
library(leafpop)
library(leafem)
library(plumber)
library(htmlwidgets)
#* Return interactive plot
#* @serializer htmlwidget
#* @get /map
function(){
dataset <- data.frame(station = c('CARATORIA', 'CENTRO', 'FONTE GRANDE', 'ILHA DO PRINCIPE',
'MOSCOSO', 'PIEDADE', 'SANTA CLARA', 'VILA RUBIM'),
lon = c(-40.35804, -40.34229, -40.33978, -40.35260, -40.34895,
-40.34157, -40.34717, -40.34976),
lat = c(-20.31472, -20.32030, -20.31325, -20.32188, -20.31468,
-20.31404, -20.31850, -20.31958),
value_no2 = c(23.93333, 123.06250, 40.00000, 10.93750, 46.38462,
36.66667, 27.69231, 56.00000),
value_pm10 = c(10.238095, NaN, 13.842105, 9.318182, 17.842105,
NaN, 9.000000, 15.333333))
my_list <- list()
loop<-for (i in unique(dataset$station)) {
name <- dataset %>% filter(station == i)
plot <- ggplot(name, aes(x = value_no2, y = station)) +
geom_col()+labs(title = i)
my_list[[i]] <- plot
}
my_list2 <- list()
loop<-for (i in unique(dataset$station)) {
name <- dataset %>% filter(station == i)
plot <- ggplot(name, aes(x = value_pm10, y = station)) +
geom_col()+labs(title = i)
my_list2[[i]] <- plot
}
list_comb <- list()
list_comb[[1]] <- my_list
list_comb[[2]] <- my_list2
test <- list()
grafico_correto <- for (i in 1:max(length(my_list),length(my_list2))){
test[[i]] <- subplot(do.call( rbind, list_comb)[,i], nrows = 2)
}
leaflet() %>%
addTiles() %>%
addCircleMarkers(data = dataset, ~lon,~lat, popup = popupGraph(test, type = "html"))
}
没有管道工功能:
Without Plumber function: Popup does work
带管道工功能:
【问题讨论】: