【发布时间】:2013-05-16 18:38:30
【问题描述】:
我有一个如下所示的嵌套列表:
dput(head(tempList))
structure(list(Species = c("RandArcBo1", "RandArcBo1", "RandArcBo1",
"RandArcBo1", "RandArcBo1", "RandArcBo1", "RandArcBo1", "RandArcBo1",
"RandArcBo1", "RandArcBo1", "RandArcBo1", "RandArcBo1", "RandArcBo1",
"RandArcBo1", "RandArcBo1", "RandArcBo1"), x = c(132.5, 156.5,
178.5, 159.5, 166.5, 133.5, 103.5, 162.5, 165.5, 143.5, -163.5,
178.5, 151.5, 163.5, -120.5, -151.5), y = c(84.567321777, 83.567321777,
60.567321777, 77.567321777, 56.567321777, 74.567321777, 85.567321777,
70.567321777, 55.567321777, 74.567321777, 66.567321777, 72.567321777,
81.567321777, 53.567321777, 85.567321777, 76.567321777), Species = c("RandArcBo2",
"RandArcBo2", "RandArcBo2", "RandArcBo2", "RandArcBo2", "RandArcBo2",
"RandArcBo2", "RandArcBo2", "RandArcBo2", "RandArcBo2", "RandArcBo2",
"RandArcBo2", "RandArcBo2", "RandArcBo2", "RandArcBo2", "RandArcBo2"
), x = c(150.5, 121.5, 169.5, 174.5, 175.5, 153.5, -97.5, 169.5,
159.5, 166.5, -114.5, -92.5, -176.5, -167.5, 136.5, -133.5),
y = c(55.567321777, 76.567321777, 58.567321777, 80.567321777,
83.567321777, 82.567321777, 83.567321777, 57.567321777, 75.567321777,
55.567321777, 74.567321777, 77.567321777, 68.567321777, 67.567321777,
74.567321777, 70.567321777)), .Names = c("Species", "x",
"y", "Species", "x", "y"))
我想要将这些数据合并到一个包含三列“物种”、“x”和“y”的表格中(每行都标有一个可以重复的物种名称,后跟一个 x,y 坐标) . Cbind 将二阶列表放在彼此相邻的列中,因此我最终得到的列数等于一阶对象数的 3*。 Rbind 将二阶列表放入行中,因此我最终得到的列数等于二阶列表的长度。有什么建议吗?
【问题讨论】:
-
您可能不想为列表中的项目重复使用名称。 (我什至没有意识到这是可能的。)例如,如果您使用
tempList[["x"]],您只会得到具有该名称的第一个项目;甚至没有第二个项目存在的警告。
标签: r nested-lists rbind cbind