【发布时间】：2019-11-18 13:07:10
【问题描述】：
已经有很多关于reshape2 库的问题，但我对一段可以一次重塑我需要的所有列的代码感兴趣。我有一个电话使用数据集，其中包含每个用户的日常电话使用情况，如频率、持续时间，按不同的应用类别划分。前 10 个样本的输入：
structure(list(X = 1:10, user_id = c(10161L, 10161L, 10161L,
10161L, 10161L, 10161L, 10161L, 10161L, 10161L, 10161L), date = c("2019-02-21",
"2019-02-21", "2019-02-21", "2019-02-21", "2019-02-22", "2019-02-22",
"2019-02-22", "2019-02-22", "2019-02-22", "2019-02-23"), categories = c("communication",
"games & entertainment", "lifestyle", "utility & tools", "communication",
"games & entertainment", "lifestyle", "social network", "utility & tools",
"communication"), frequency = c(30L, 13L, 3L, 15L, 99L, 19L,
8L, 2L, 73L, 57L), cat_duration = c(1663.83800005913, 1855.2380001545,
38.9109997749329, 1016.48200011253, 7044.4249997139, 8498.35199904442,
71.5590000152588, 741.676999807358, 2657.03099822998, 5145.73099899292
), dur_pro = c(0.363722652841753, 0.40556357472605, 0.00850612383078189,
0.222207648601416, 0.370504849244312, 0.446974824255909, 0.00376367929444972,
0.0390088509726144, 0.139747796232715, 0.314487675459045), freq_pro = c(0.491803278688525,
0.213114754098361, 0.0491803278688525, 0.245901639344262, 0.492537313432836,
0.0945273631840796, 0.0398009950248756, 0.00995024875621891,
0.36318407960199, 0.463414634146341), monetary = c(55.4612666686376,
142.7106153965, 12.970333258311, 67.7654666741689, 71.1558080779182,
447.281684160233, 8.94487500190735, 370.838499903679, 36.39768490726,
90.2759824384723), recency = c(6504.5680000782, 5023.14100003242,
26999.1610000134, 32.4110000133514, 518.858000040054, 209.592000007629,
30790.6349999905, 4608.17300009727, 14603.4340000153, 68.6960000991821
)), row.names = c(NA, 10L), class = "data.frame")
通过使用reshape2 库，我可以将其转换为我需要的格式，但它一次只接受一个变量作为value.var 的参数，例如频率：
dcast(phone_usage, user_id+date~categories, value.var = 'frequency')
有没有办法同时投射 6 个功能？我相信有一种比单独投射并组合它们更简单的方法...(frequency,cat_duration,dur_pro,freq_pro,monetary,recency)
提前感谢您的贡献！
PS：我知道将数据帧转换为宽格式时会出现缺失值问题，但现在让我们忽略这个问题。
【问题讨论】：
标签： r