【发布时间】:2018-07-18 12:32:24
【问题描述】:
过去几天我一直在 Stack Overflow 上尝试解决我遇到的这个问题。
我正在分析从国家学生信息交换所收到的数据,特别是毕业数据。所以我有一些虚拟数据
df <- data.frame(id=c('1', '1', '1'), grad_date=c('20160501', '20170524', '20180524'), order=c('1', '2', '3'), inst_name=c('community college 1', 'univ 1', 'univ 2'), inst_state=c('CA', 'CA', 'CA'), level=c('Associate of Applied Sciences', 'Bachelors of Applied Sciences', 'Masters of Applied Sciences'), deg_maj_1=c('NETWORK SECURITY', 'INFO ASSUR CYBR-SECURITY', 'CISCO CCNA PREPARATION'), deg_cip_1=c('111003', '520299', '111003'), deg_maj_2=c('NA', 'NA', 'NA'), deg_cip_2=c('NA', 'NA', 'NA'), deg_maj_3=c('NA', 'NA', 'NA'), deg_cip_3=c('NA', 'NA', 'NA'), deg_maj_4=c('NA', 'NA', 'NA'), deg_cip_4=c('NA', 'NA', 'NA'))
我正在尝试广泛获取这些数据:
df_wide<- dcast(df, id ~ order, value.var = c("inst_name", "inst_state", "level", "deg_maj_1", "deg_cip_1", "deg_maj_2", "deg_cip_2", "deg_maj_3", "deg_cip_3", "deg_maj_4", "deg_cip_4"))
我收到了这个错误:
.subset2(x, i, exact = exact) 中的错误: 递归索引在第 2 级失败
如果这有帮助:
str(df)
'data.frame': 3 obs. of 14 variables:
$ id : Factor w/ 1 level "1": 1 1 1
$ grad_date : Factor w/ 3 levels "20160501","20170524",..: 1 2 3
$ order : Factor w/ 3 levels "1","2","3": 1 2 3
$ inst_name : Factor w/ 3 levels "community college 1",..: 1 2 3
$ inst_state: Factor w/ 1 level "CA": 1 1 1
$ level : Factor w/ 3 levels "Associate of Applied Sciences",..: 1 2 3
$ deg_maj_1 : Factor w/ 3 levels "CISCO CCNA PREPARATION",..: 3 2 1
$ deg_cip_1 : Factor w/ 2 levels "111003","520299": 1 2 1
$ deg_maj_2 : Factor w/ 1 level "NA": 1 1 1
$ deg_cip_2 : Factor w/ 1 level "NA": 1 1 1
$ deg_maj_3 : Factor w/ 1 level "NA": 1 1 1
$ deg_cip_3 : Factor w/ 1 level "NA": 1 1 1
$ deg_maj_4 : Factor w/ 1 level "NA": 1 1 1
$ deg_cip_4 : Factor w/ 1 level "NA": 1 1 1
有人可以帮忙吗?我已经不知所措了
编辑添加: 期望的输出(是的,我知道它很糟糕,但它是必需的)
df_wide <- data.frame(id=c('1'), grad_date=c('20160501'), inst_name_1=c('community college 1'), inst_state_1=c('CA'), level_1=c('Associate of Applied Sciences'), deg_maj_1_1=c('NETWORK SECURITY'), deg_cip_1_1=c('111003'), deg_maj_2_1=c('NA'), deg_cip_2_1=c('NA'), deg_maj_3_1=c('NA'), deg_cip_3_1=c('NA'), deg_maj_4_1=c('NA'), deg_cip_4_1=c('NA'), inst_name_2=c('univ 1'), inst_state_2=c('CA'), level_2=c('Bachelors of Applied Sciences'), deg_maj_1_2=c('INFO ASSUR CYBR-SECURITY'), deg_cip_1_2=c('520299'), deg_maj_2_2=c('NA'), deg_cip_2_2=c('NA'), deg_maj_3_2=c('NA'), deg_cip_3_2=c('NA'), deg_maj_4_2=c('NA'), deg_cip_4_2=c('NA'), inst_name_3=c('univ 2'), inst_state_3=c('CA'), level_3=c('Masters of Applied Sciences'), deg_maj_1_2=c('CISCO CCNA PREPARATION'), deg_cip_1_3=c('111003'), deg_maj_2_3=c('NA'), deg_cip_2_3=c('NA'), deg_maj_3_3=c('NA'), deg_cip_3_3=c('NA'), deg_maj_4_3=c('NA'), deg_cip_4_3=c('NA'))
【问题讨论】:
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您的预期输出应该是什么样的?
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谢谢@jaySf 我已经更新了问题