【发布时间】:2021-07-30 20:38:27
【问题描述】:
这是我为帮助我定义策略而编写的代码。它工作得很好,但我觉得代码太长了,我想知道是否有一种有效的方法可以用 for 循环来做同样的事情。 代码搜索一组烛台,其主体包含在另一个先前的柱中。用我笨拙的方法,我只能设计最少 2 根蜡烛,最多 7 根蜡烛。是否可以使用 for 循环来获取满足此条件的尽可能多的蜡烛? 提前致谢。
def eATR(df1,n=14):
"""This calculates the Average True Range of of a dataframe of the open,
high, low, and close data of an instrument"""
df = df1[['Open', 'High', 'Low', 'Close',]]
# True Range
df['TR'] = 0
for i in range(len(df)):
try:
df.iloc[i, 4] = max(df.iat[i,1] - df.iat[i,2],
abs(df.iat[i,1] - df.iat[i-1,3]),
abs(df.iat[i,2] - df.iat[i-1,3]))
except ValueError:
pass
# eATR
df['eATR']= df['TR'].ewm(span=n, adjust=False).mean()
df.drop(['TR'], axis = 1, inplace=True)
return df['eATR']
def contraction(data):
df = data.copy()
e_ATR = eATR(df)
bodyHi = df[['Open', 'Close']].apply(max,axis=1)
bodyLo = df[['Open', 'Close']].apply(min,axis=1)
topWick = abs(df['High'] - bodyHi)
botWick = abs(bodyLo - df['Low'])
bodyLen = abs(bodyHi - bodyLo)
canLen = df['High'] - df['Low']
per = 1.5
contraction = np.where((df['High'].shift(7) >= bodyHi.shift(6))
& (df['High'].shift(7) >= bodyHi.shift(5))
& (df['High'].shift(7) >= bodyHi.shift(4))
& (df['High'].shift(7) >= bodyHi.shift(3))
& (df['High'].shift(7) >= bodyHi.shift(2))
& (df['High'].shift(7) >= bodyHi.shift(1))
& (df['High'].shift(7) >= bodyHi.shift(0))
& (df['Low'].shift(7) <= bodyLo.shift(6))
& (df['Low'].shift(7) <= bodyLo.shift(5))
& (df['Low'].shift(7) <= bodyLo.shift(4))
& (df['Low'].shift(7) <= bodyLo.shift(3))
& (df['Low'].shift(7) <= bodyLo.shift(2))
& (df['Low'].shift(7) <= bodyLo.shift(1))
& (df['Low'].shift(7) <= bodyLo.shift(0))
& (canLen.shift(0) <= canLen.shift(7) * per)
& (canLen.shift(1) <= canLen.shift(7) * per)
& (canLen.shift(2) <= canLen.shift(7) * per)
& (canLen.shift(3) <= canLen.shift(7) * per)
& (canLen.shift(4) <= canLen.shift(7) * per)
& (canLen.shift(5) <= canLen.shift(7) * per)
& (canLen.shift(6) <= canLen.shift(7) * per)
| (df['High'].shift(6) >= bodyHi.shift(5))
& (df['High'].shift(6) >= bodyHi.shift(4))
& (df['High'].shift(6) >= bodyHi.shift(3))
& (df['High'].shift(6) >= bodyHi.shift(2))
& (df['High'].shift(6) >= bodyHi.shift(1))
& (df['High'].shift(6) >= bodyHi.shift(0))
& (df['Low'].shift(6) <= bodyLo.shift(5))
& (df['Low'].shift(6) <= bodyLo.shift(4))
& (df['Low'].shift(6) <= bodyLo.shift(3))
& (df['Low'].shift(6) <= bodyLo.shift(2))
& (df['Low'].shift(6) <= bodyLo.shift(1))
& (df['Low'].shift(6) <= bodyLo.shift(0))
& (canLen.shift(0) <= canLen.shift(6) * per)
& (canLen.shift(1) <= canLen.shift(6) * per)
& (canLen.shift(2) <= canLen.shift(6) * per)
& (canLen.shift(3) <= canLen.shift(6) * per)
& (canLen.shift(4) <= canLen.shift(6) * per)
& (canLen.shift(5) <= canLen.shift(6) * per)
| (df['High'].shift(5) >= bodyHi.shift(4))
& (df['High'].shift(5) >= bodyHi.shift(3))
& (df['High'].shift(5) >= bodyHi.shift(2))
& (df['High'].shift(5) >= bodyHi.shift(1))
& (df['High'].shift(5) >= bodyHi.shift(0))
& (df['Low'].shift(5) <= bodyLo.shift(4))
& (df['Low'].shift(5) <= bodyLo.shift(3))
& (df['Low'].shift(5) <= bodyLo.shift(2))
& (df['Low'].shift(5) <= bodyLo.shift(1))
& (df['Low'].shift(5) <= bodyLo.shift(0))
& (canLen.shift(0) <= canLen.shift(5) * per)
& (canLen.shift(1) <= canLen.shift(5) * per)
& (canLen.shift(2) <= canLen.shift(5) * per)
& (canLen.shift(3) <= canLen.shift(5) * per)
& (canLen.shift(4) <= canLen.shift(5) * per)
| (df['High'].shift(4) >= bodyHi.shift(3))
& (df['High'].shift(4) >= bodyHi.shift(2))
& (df['High'].shift(4) >= bodyHi.shift(1))
& (df['High'].shift(4) >= bodyHi.shift(0))
& (df['Low'].shift(4) <= bodyLo.shift(3))
& (df['Low'].shift(4) <= bodyLo.shift(2))
& (df['Low'].shift(4) <= bodyLo.shift(1))
& (df['Low'].shift(4) <= bodyLo.shift(0))
& (canLen.shift(0) <= canLen.shift(4) * per)
& (canLen.shift(1) <= canLen.shift(4) * per)
& (canLen.shift(2) <= canLen.shift(4) * per)
& (canLen.shift(3) <= canLen.shift(4) * per)
| (df['High'].shift(3) >= bodyHi.shift(2))
& (df['High'].shift(3) >= bodyHi.shift(1))
& (df['High'].shift(3) >= bodyHi.shift(0))
& (df['Low'].shift(3) <= bodyLo.shift(2))
& (df['Low'].shift(3) <= bodyLo.shift(1))
& (df['Low'].shift(3) <= bodyLo.shift(0))
& (canLen.shift(0) <= canLen.shift(3) * per)
& (canLen.shift(1) <= canLen.shift(3) * per)
& (canLen.shift(1) <= canLen.shift(3) * per)
| (df['High'].shift(2) >= bodyHi.shift(1))
& (df['High'].shift(2) >= bodyHi.shift(0))
& (df['Low'].shift(2) <= bodyLo.shift(1))
& (df['Low'].shift(2) <= bodyLo.shift(0))
& (canLen.shift(0) <= canLen.shift(2) * per)
& (canLen.shift(1) <= canLen.shift(2) * per), 1, 0)
return contraction
当满足上述条件时,这是我的图表上以“burlywood”着色的输出。
感谢期待!
【问题讨论】:
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您好!如果您正在寻找对工作代码的一般审查和批评,您应该考虑将其发布到 CodeReview.SE。
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好的,布莱恩。感谢那。我只是想缩短我的代码。代码正在做我要求它做的事情