【问题标题】:Subsetting data frame in R based on range of values in a column根据列中的值范围对 R 中的数据框进行子集化
【发布时间】:2019-01-24 17:55:55
【问题描述】:

我有一个包含多列和多行的数据框 (df),例如:

    A     B   C 

    0.6   a.  b

    0.9   c.  d

    1.1.  e.  f

    1.2   g.  h

    1.4   I   l

    1.5.  m.  n

    5.0   o.  p

    5.3   q.  r

    5.6.  s.  t

    6.1.  u  v

    6.5.  w. z

    6.9.  y  a

    7.0.  b. c

我正在寻找的代码应该计算 A 列中每个连续值之间的差异(0.9-0.3 = 0.3、1.1-0.9=0.2 等等),如果差异大于某个阈值(这里我们设置为 3,但可以不同)它将子集一定数量的行(在这种情况下假设为 3,但它也可以不同)在差异大于阈值设置的差距之前和之后。 因此,在这种情况下,5.0 - 1.5 = 3.5 大于 3,将保留 1.5 之前的 3 行和 5.0 之后的 3 行,其余的将被删除。 知道如何编写这样的代码吗?

输出:

    A     B   C 

    1.1.  e.  f

    1.2   g.  h

    1.4   I   l

    1.5.  m.  n

    5.0   o.  p

    5.3   q.  r

    5.6.  s.  t

    6.1.  u  v

我有多个数据框,因此 A 列中的值不同,代码应逐个查看每个数据框,并根据设置的阈值查找 A 列中的间隙在哪里。

dput 格式的数据。

输入:data.frame df1

df1 <-
structure(list(A = c(0.6, 0.9, 1.1, 1.2, 1.4, 
1.5, 4, 4.3, 4.6, 5.1, 5.5, 5.9, 6), 
B = structure(c(1L, 3L, 4L, 5L, 6L, 7L, 8L, 
9L, 10L, 11L, 12L, 13L, 2L), .Label = c("a.", 
"b.", "c.", "e.", "g.", "I", "m.", "o.", 
"q.", "s.", "u", "w.", "y"), class = "factor"), 
C = structure(c(2L, 4L, 5L, 6L, 7L, 8L, 9L, 
10L, 11L, 12L, 13L, 1L, 3L), .Label = c("a", 
"b", "c", "d", "f", "h", "l", "n", "p", 
"r", "t", "v", "z"), class = "factor")), 
row.names = c(NA, -13L), class = "data.frame")

输出:data.frame out

out <-
structure(list(A = c(1.1, 1.2, 1.4, 1.5, 4, 
4.3, 4.6, 5.1), B = structure(1:8, 
.Label = c("e.", "g.", "I", "m.", "o.", 
"q.", "s.", "u"), class = "factor"), 
C = structure(1:8, .Label = c("f", "h", "l", 
"n", "p", "r", "t", "v"), class = "factor")), 
row.names = c(NA, -8L), class = "data.frame")

这是我的 df:

structure(list(POS = c(207687374L, 207689227L, 207690871L, 207691563L, 
207693563L, 207694165L, 207694357L, 207738077L, 207739127L, 207740272L, 
207740868L, 207747296L, 207747984L, 207748107L), SNP = c("rs12130494", 
"rs4844601", "rs10863358", "rs77357299", "rs12043913", "rs61822967", 
"rs11117991", "rs7515905", "rs3886100", "rs12038575", "rs34883952", 
"rs1752684", "rs17046851", "rs10127904"), Std_iHS = c(-1.52176, 
-1.51905, -1.50286, 0.656487, -1.45251, 0.84325, -1.06089, -1.41041, 
1.29513, 1.21325, 0.456717, -1.00933, -1.71468, 0.265969)), row.names = 
21:34, class = "data.frame")

输出:

structure(list(POS = c(207691563L, 
207693563L, 207694165L, 207694357L, 207738077L, 207739127L, 207740272L, 
207740868L, ), SNP = c( "rs77357299", "rs12043913", "rs61822967", 
"rs11117991", "rs7515905", "rs3886100", "rs12038575", "rs34883952", 
), Std_iHS = c( 0.656487, -1.45251, 0.84325, -1.06089, -1.41041, 
1.29513, 1.21325, 0.456717, )), row.names = 21:34, class = "data.frame")

【问题讨论】:

  • 另外,为什么包含所需结果 (e. f) 中的第一行?大跳跃前4行
  • 当然,我会尝试使用 dput 并添加可重现的数据集;是的,第 1.1 行。 e. f 应该包括在内,因为它应该在间隙的第一个值 (1.5) 之前占用 3 行,在间隙的第二个值 (4.0) 之后占用 3 行
  • 看看这些问题,它们可能会对你有所帮助:stackoverflow.com/questions/53622509/…, stackoverflow.com/questions/42925017/…
  • 是的,我可以通过设置特定值来获取那些存在间隙位置的行中的“哪个”的索引,我试过了,我可以为单个数据帧做到这一点但我的问题是,间隙前后的两个值总是不同,具体取决于数据框,所以我不知道该怎么做,无论如何,谢谢

标签: r


【解决方案1】:

使用基础 R,您可以执行以下操作:

limit = 2
df1[match(unique(c(sapply(which(diff(df1$A)>limit),function(x)(x-3):(x+4)))),1:nrow(df1)),]
     A  B C
3  1.1 e. f
4  1.2 g. h
5  1.4  I l
6  1.5 m. n
7  4.0 o. p
8  4.3 q. r
9  4.6 s. t
10 5.1  u v

【讨论】:

    【解决方案2】:

    看起来您的示例数据框没有超过 3.0 的任何跳转,但这段代码应该可以工作:

    limit <- 2.0
    
    structure(list(A = c(0.6, 0.9, 1.1, 1.2, 1.4, 
                     1.5, 4, 4.3, 4.6, 5.1, 5.5, 5.9, 6), 
               B = structure(c(1L, 3L, 4L, 5L, 6L, 7L, 8L, 
                               9L, 10L, 11L, 12L, 13L, 2L), .Label = c("a.", 
                                                                       "b.", "c.", "e.", "g.", "I", "m.", "o.", 
                                                                       "q.", "s.", "u", "w.", "y"), class = "factor"), 
               C = structure(c(2L, 4L, 5L, 6L, 7L, 8L, 9L, 
                               10L, 11L, 12L, 13L, 1L, 3L), .Label = c("a", 
                                                                       "b", "c", "d", "f", "h", "l", "n", "p", 
                                                                       "r", "t", "v", "z"), class = "factor")), 
          row.names = c(NA, -13L), class = "data.frame") %>%
    mutate(diffA = A - lag(A, 1)) %>%
      mutate(over_limit = diffA > limit) %>%
      mutate(before_limit = lag(over_limit, 1) | lag(over_limit, 2),
         after_limit = lead(over_limit, 1) | lead(over_limit, 2)) %>%
      rowwise() %>%
      mutate(subset_filter = any(over_limit, after_limit, before_limit)) %>%
      ungroup() %>%
      filter(subset_filter) %>%
      select(-c(subset_filter, diffA, over_limit, before_limit, after_limit))
    

    以 dput() 格式输出:

    structure(list(A = c(1.4, 1.5, 4, 4.3, 4.6),
    B = structure(6:10, .Label = c("a.", "b.", "c.", "e.", "g.", "I", "m.", "o.", "q.", "s.", "u", "w.", "y"), class = "factor"), 
    C = structure(7:11, .Label = c("a", "b", "c", "d", "f", "h", "l", "n", "p", "r", "t", "v", "z"), class = "factor")), 
    class = c("tbl_df",  "tbl", "data.frame"), 
    row.names = c(NA, -5L), .Names = c("A", "B", "C"))
    

    【讨论】:

    • 非常感谢,我正在尝试这段代码,非常有用
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