我需要计算在两个不相关的复杂查询中重复的条目答案

【问题标题】：I need to Count entries that are duplicated on two unrelated complex queries我需要计算在两个不相关的复杂查询中重复的条目
【发布时间】：2017-07-20 21:21:43
【问题描述】：

我编写了两个单独的查询并尝试合并，但这对我来说太复杂了。第一个查询是返回经销商编号列表的子查询，没有任何重复的编号。第二个查询返回经销商编号列表，其中包含多个重复的经销商编号，以及经销商余额。我需要查看第一个查询中的经销商编号出现在第二个查询中的次数。目前，我将两个查询结果复制并粘贴到 Excel 中，然后使用 Countif 函数查看第一个查询中的经销商出现在第二个查询中的次数。

有没有办法在 SQL 中完成整个过程？

查询 1

SELECT DISTINCT(X.PARENTS) AS "UNIQUE PARENTS" FROM ( SELECT

CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END AS "PARENTS",

CASE WHEN ((SUM(decode(CUSTMR_COLLAT_TYPE_DESCR,'New Car',1,0)) ) ) <> 0 THEN 'Y' ELSE 'N' END AS "FRANCHISE"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL AND EXTRCT_FILE_DT = '30-JUN-2017'

GROUP BY CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END, CUSTMR_NBR
) X

WHERE X.FRANCHISE = 'N'

查询 2

SELECT CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END AS "DUPLICATE PARENTS",

SUM(CURR_PRINCPL_AMT)

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL

AND EXTRCT_FILE_DT = '30-JUN-2017'

AND (CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END <>CUSTMR_NBR)

GROUP BY CASE WHEN  PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END, CUSTMR_NBR

【问题讨论】：

标签： sql count subquery case-when

【解决方案1】：

Select Count(PARENT_CUSTMR_NBR) From
(
SELECT DISTINCT(X.PARENTS) AS "UNIQUE PARENTS" FROM ( SELECT

CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR 
END AS "PARENTS",

CASE WHEN ((SUM(decode(CUSTMR_COLLAT_TYPE_DESCR,'New Car',1,0)) ) ) <> 0 
THEN 'Y' ELSE 'N' END AS "FRANCHISE"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL AND EXTRCT_FILE_DT = '30-JUN-2017'

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR ) X

WHERE X.FRANCHISE = 'N')
Where PARENT_CUSTMR_NBR
IN
(SELECT CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END AS "DUPLICATE PARENTS",

SUM(CURR_PRINCPL_AMT)

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL

AND EXTRCT_FILE_DT = '30-JUN-2017'

AND (CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END <>CUSTMR_NBR)

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR)

【讨论】：

我认为这非常接近，感谢您的帮助！不幸的是，代码“CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END”部分不能缩短为“PARENT_CUSTMR_NBR”。我希望子查询可以修复它，但没有运气。
您可以为此使用别名，例如：CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR END AS "PARENT_CUSTMR_NBR"

【解决方案2】：

我得到了它的工作，感谢您的帮助 Suresh！这是最终的查询：

Select Count(DUPPARENTS) From

(SELECT CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END AS "DUPPARENTS"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL

AND EXTRCT_FILE_DT = '30-JUN-2017'

AND (CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END <>CUSTMR_NBR)

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR)

Where (DUPPARENTS) IN

(SELECT DISTINCT(X.UNIPARENTS) FROM ( SELECT

CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE PARENT_CUSTMR_NBR 
END AS "UNIPARENTS",

CASE WHEN ((SUM(decode(CUSTMR_COLLAT_TYPE_DESCR,'New Car',1,0)) ) ) <> 0 
THEN 'Y' ELSE 'N' END AS "FRANCHISE"

FROM MONTH_END_TABLE

WHERE TRUST_ID IS NOT NULL AND EXTRCT_FILE_DT = '30-JUN-2017'

GROUP BY CASE WHEN PARENT_CUSTMR_NBR IS NULL THEN CUSTMR_NBR ELSE 
PARENT_CUSTMR_NBR END, CUSTMR_NBR ) X

WHERE X.FRANCHISE = 'N')

【讨论】：