每小时 Oracle SQL 计数记录

Question

所以，我要做的基本上是计算每个承运人每小时的发货量，但我很难将其汇总到我想要的列中。目标是在第 1 小时或第 2 小时下有 1 或 2 个，而不是有总和（总出货量）。基本上是 24 小时，所以我们可以看到一天中的时间趋势......

代码：

    select router_destination_code, 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then '1' else NULL end as "Hour 1",
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then '2' else NULL end as "Hour 2",
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then '3' else NULL end as "Hour 3",
--case when app_last_updated_date_utc between 'dec/07/2013 16:00:00' and 'dec/14/2013 17:00:00' then count(Router_Destination_code) else NULL end as "Hour_1"
count(Router_Destination_code) as Shipments
from booker.routing_container_history
where 
app_last_updated_by_module in ('ManualSlam', 'slam')
and app_last_updated_date_utc between 'dec/07/2013 16:00:00' and 'dec/14/2013 16:00:00'
group by 
router_destination_code, 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then '1' else NULL end, 
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then '2' else NULL end, 
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then '3' else NULL end
order by 
case when to_char(app_last_updated_date_utc, 'HH24') = '00' then '1' else NULL end, 
case when to_char(app_last_updated_date_utc, 'HH24') = '01' then '2' else NULL end, 
case when to_char(app_last_updated_date_utc, 'HH24') = '02' then '3' else NULL end, 
count(Router_Destination_code) desc;

输出：

但是，我们的目标是在小时内发货。

谢谢。

这是我采用的一种新方法。但它显示了很多零，并且希望它只显示整个数字。

select router_destination_code, 
count(case when to_char(app_last_updated_date_utc, 'HH24') = '16' then router_destination_code else NULL end) as "Hour 1",
count(case when to_char(app_last_updated_date_utc, 'HH24') = '17' then router_destination_code else NULL end) as "Hour 2"
--case when app_last_updated_date_utc between 'dec/07/2013 16:00:00' and 'dec/14/2013 17:00:00' then count(Router_Destination_code) else NULL end as "Hour_1"
--count(Router_Destination_code) as Shipments
from booker.routing_container_history
where 
app_last_updated_by_module in ('ManualSlam', 'slam')
and app_last_updated_date_utc between 'dec/07/2013 16:00:00' and 'dec/14/2013 16:00:00'
group by 
router_destination_code, 
case when to_char(app_last_updated_date_utc, 'HH24') = '16' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '17' then router_destination_code else NULL end
order by 
case when to_char(app_last_updated_date_utc, 'HH24') = '16' then router_destination_code else NULL end,
case when to_char(app_last_updated_date_utc, 'HH24') = '17' then router_destination_code else NULL end,
count(Router_Destination_code) desc;

Answer 1

我不知道我是否理解你，但你可以尝试从日期中提取小时然后分组：

检查这个小提琴（抱歉语法错误）： http://sqlfiddle.com/#!4/a0a97/6

create table a (id number, data date);
insert into a (id, data)
values (1, to_date( '2013-01-01 13:12:01', 'yyyy-mm-dd hh24:mi:ss'));
insert into a (id, data)
values (1, to_date( '2013-01-01 13:12:01', 'yyyy-mm-dd hh24:mi:ss'));
insert into a (id, data)
values (1, to_date( '2013-01-01 14:12:01', 'yyyy-mm-dd hh24:mi:ss'));

select to_char(data,'HH24'), count(1) from a group by to_char(data,'HH24');