SQL搜索，在表中搜索a|b|c|d，返回按记录中元素个数排序的结果答案

【问题标题】：SQL search, search for a|b|c|d in a table and return results ordered by number of elements in the recordSQL搜索，在表中搜索a|b|c|d，返回按记录中元素个数排序的结果
【发布时间】：2010-08-24 06:56:53
【问题描述】：

问题：有两个表 - DAYS(name), ACTIONS(day_name,name)

DAYS 的记录是：

Sunday, Monday, Wednesday

ACTIONS 的记录是：

{eat,sunday},
{sleep,sunday},
{write,sunday},
{drink,sunday}

{eat,wednesday},
{sleep,wednesday},
{write,wednesday},

{eat,monday},
{sleep,monday},

我想在 ACTIONS 中搜索窗帘操作次数最多的日子，并返回从高到低排序的结果。含义：如果我搜索“吃”、“睡”、“写”和“喝” - 结果将是： sunday, wednesday, monday.

【问题讨论】：

标签： sql search count sql-order-by

【解决方案1】：

SELECT d.name
    FROM ACTIONS a JOIN DAYS d ON a.day_name=d.name
        WHERE a.name IN ('eat', 'sleep', 'write', 'drink')  -- Your search
            GROUP BY a.name
                ORDER BY COUNT(*) DESC;

【讨论】：

【解决方案2】：

你在找这个吗...

SELECT day_name, number FROM
(
  SELECT day_name, COUNT(*) 
  FROM ACTIONS 
  WHERE name in ('eat', 'sleep', 'write') 
  GROUP BY day_name
) AS Test
ORDER BY number DESC

【讨论】：

【解决方案3】：

select 
    day_name, count(day_name) qty
from
    actions
where 
    name in ('eat', 'sleep', 'write', 'drink')
group by day_name
order by qty desc

【讨论】：