一行sql中有多个where子句

Question

我想把下面的语句融合到一个查询中。

SELECT COUNT(*) AS count1 WHERE Month='11' AND Flag = 1
SELECT COUNT(*) AS count2 WHERE Month='11' AND Flag = 2
SELECT COUNT(*) AS count1 WHERE Month='12' AND Flag = 1
    SELECT COUNT(*) AS count2 WHERE Month='12' AND Flag = 2

我希望它显示为一个查询，其中包含 count1 和 count2 列以及第 11 个月和第 12 个月的行。

这有语法吗？

Answer 1

您可以将SUM 和CASE 组合在一起，一次性获得各种计数：

SELECT
    Month,
    SUM(CASE WHEN Flag=1 THEN 1 ELSE 0 END) as count1,
    SUM(CASE WHEN Flag=2 THEN 1 ELSE 0 END) as count2
from
    ...
WHERE Month in ('11','12')
GROUP BY
    Month /* Other columns? */

Answer 2

只有两列，它可以是这样的：

select
   (SELECT COUNT(*) FROM tablename WHERE Month='11' AND Flag = 1) as 'count1'
   (SELECT COUNT(*) FROM tablename WHERE Month='11' AND Flag = 2) as 'count2'

UNION ALL

select
   (SELECT COUNT(*) FROM tablename WHERE Month='12' AND Flag = 1), 
   (SELECT COUNT(*) FROM tablename WHERE Month='12' AND Flag = 2)

将tablename 替换为您的表名。

Answer 3

这个怎么样：

select
    month, flag, count(*)
from
    table
where
    month in ('11', '12') and
    flag in (1, 2)
group by
    month, flag;