如何获得每个年龄类别的总数？答案

【问题标题】：How to get totals for each age category?如何获得每个年龄类别的总数？
【发布时间】：2019-08-15 17:17:34
【问题描述】：

proc sql;
 create table final as select drink,
 count(distinct id) as total_persons,
 count(distinct case when age_cat = '20-25' then id end) as tot_20_25, 
 count(distinct case when age_cat = '25-30' then id end) astot_25_30, 
 count(distinct case when age_cat = '30-35' then id end) as tot_30_35 
 from old_table
 group by drink
 order by total_persons
 quit;

这张表给了我我想要的东西，但我想要多一行作为所有人和每个类别的总数。如果从上面的代码中按声明删除该组，我可以获得具有正确数字的单行。有什么办法可以同时满足这两种情况，按饮料分类，并且每个类别的总数都在同一张表中？

【问题讨论】：

您显然在使用 proc-sql，所以我更改了标签。如果这是对 MySQL 的直通查询，您应该清楚。
SAS GROUP BY Rollup?

标签： sql proc-sql

【解决方案1】：

你可以使用union all:

proc sql;
 create table final as
     select drink,
            count(distinct id) as total_persons,
            count(distinct case when age_cat = '20-25' then id end) as tot_20_25, 
            count(distinct case when age_cat = '25-30' then id end) as tot_25_30, 
            count(distinct case when age_cat = '30-35' then id end) as tot_30_35 
     from old_table
     group by drink
     union all
     select 'Total',
            count(distinct id) as total_persons,
            count(distinct case when age_cat = '20-25' then id end) as tot_20_25, 
            count(distinct case when age_cat = '25-30' then id end) as tot_25_30, 
            count(distinct case when age_cat = '30-35' then id end) as tot_30_35 
     from old_table;

【讨论】：

感谢戈登的帮助。