如何平均查询底部的列

Question

忽略'?DATE1::?'，它只是用户输入日期范围的前缀。

Select
       STARTDATEKEY 
       round(avg(Minutes),2) as Time  /*average for 1 day */
from   Table
where To_Date(to_char(StartDate, 'DD-MON-YYYY')) >= To_Date('?DATE1::?','MM/DD/YYYY')
and To_Date(to_char(RESTOREDDATETIME, 'DD-MON-YYYY')) <= To_Date('?DATE2::?','MM/DD/YYYY')
and FLAG = 0
group by STARTDATEKEY 

输出将是

我需要帮助显示 20130110 52.67

底部时间列的平均值

编辑/审稿人注意：我不知道应该标记 Oracle 还是 SQL。

Answer 1

您可以使用ROLLUP 分组功能。
应该是这样的：

Select
       STARTDATEKEY 
       round(avg(Minutes),2) as Time  /*average for 1 day */
from   Table
where To_Date(to_char(StartDate, 'DD-MON-YYYY')) >= To_Date('?DATE1::?','MM/DD/YYYY')
and To_Date(to_char(RESTOREDDATETIME, 'DD-MON-YYYY')) <= To_Date('?DATE2::?','MM/DD/YYYY')
and FLAG = 0
group by ROLLUP(STARTDATEKEY)

Here is a simplified sqlfiddle demo