错误（24,66）：PL/SQL：ORA-00984：此处不允许列

Question

我正在制作一个触发器，检查一个人是否可以参加世界锦标赛或欧洲锦标赛，如果他们开车，计算他们在燃料上的花费（燃料成本 * 花费 * 距离/100）。我需要将该信息放在另一个表中，但我收到此消息：

Error(24,66): PL/SQL: ORA-00984: column not allowed here

那是因为我在代码底部的 INSERT 语句中添加了“fuelcost * 花 * :new.distance/100”。我的问题是，我怎样才能以某种不同的方式将该值计入餐桌成本。列 cost.money 不是计算列，因为它不仅仅是该表中的燃料成本，因此这不是解决方案。

CREATE OR REPLACE TRIGGER check_norm_fuel_cost 
  INSTEAD OF INSERT OR UPDATE ON insert_travel_view
  FOR EACH ROW
  DECLARE 
    hasnorm char(1);
    spends number;
    fuelcost number;

  BEGIN
    SELECT norms.norm INTO hasnorm
      FROM norms JOIN competitions
        ON competitions.competitionID=norms.competitionID
      WHERE :new.personID = norms.personID 
           AND (competitions.name LIKE 'European championship' 
              OR competitions.name LIKE 'World championship');

      IF hasnorm = 'Y' OR hasnorm IS NULL THEN
        INSERT INTO travel(travelID, personID, competitionID, vehicleID, distance) 
          VALUES (:new.travelID, :new.personID, :new.competitionID, :new.vehicleID, :new.distance);
        IF :new.distance IS NOT NULL THEN
          SELECT vehicles.consumption INTO spends FROM vehicles 
            WHERE :new.vehicleID = vehicles.vehicleID;
          SELECT fuels.cost INTO fuelcost FROM fuels JOIN vehicles ON vehicles.fuelID = fuels.fuelID
            WHERE :new.vehicleID = vehicles.vehicleID;

          INSERT INTO COSTS(costID, costtype, travelID, money)
            VALUES(35, 'fuel', :new.travelID, fuelcost*spends*:new.distance/100);

        END IF;
      END IF;
  END;

Answer 1

尝试将插入语句中的显式值更改为 select like insert into(...) select .... from ，很抱歉从移动端写入格式错误。

Answer 2

你似乎有三个问题； ORA-00984 是因为您的最终插入正在执行：

VALUES(35, 'fuel', :new.travelID, fuelcost*spends*distance/100);

distance 被解释为列名，因为范围内没有具有该名称的变量；大概应该是：

VALUES(35, 'fuel', :new.travelID, fuelcost*spends*:new.distance/100);

虽然您可以避免使用 spends 和 fuelcost 局部变量，而改为使用 insert ... select：

INSERT INTO COSTS(costID, costtype, travelID, money)
SELECT 35, 'fuel', :new.travelID, fuels.cost*vehicles.consumption*:new.distance/100
FROM fuels JOIN vehicles ON vehicles.fuelID = fuels.fuelID
WHERE vehicles.vehicleID = :new.vehicleID;

您似乎还有两个错别字：

    INSERT INTO travel(travelID, personID, competitonID, vehicleID, distance)

缺少i，应该（我认为）是：

    INSERT INTO travel(travelID, personID, competitionID, vehicleID, distance)

和：

        WHERE :new.vehicleID = vehicle.vehicleID;

缺少s 并且应该（我认为）是：

        WHERE :new.vehicleID = vehicles.vehicleID;