oracle sql组总和

Question

我有带有 ID、Sub_ID 和值列的表

ID  SUB_ID  Value
100 1   100
100 2   150
101 1   100
101 2   150
101 3   200
102 1   100

SUB ID 可以从 1..maxvalue 变化（在本例中为 3）。我需要每个 Sub_ID 的值总和。如果某个特定 ID 的 SUB_ID 小于 MAXVALUE，则它应该采用每个 ID 的 MAX(SUB_ID) 如下所示（在此示例中，对于 SUB_ID 3 的 ID=100，它应该采用 150，即 2

SUB_ID  SUM(values) Remarks
1           300         (100+100+100)
2           400         (150+150+100)
3           450         (150+200+100)

这可以在 PL/SQL 中轻松完成。我们可以使用模型子句或任何其他选项来使用 SQL 吗

Answer 1

SQL Fiddle

Oracle 11g R2 架构设置：

CREATE TABLE TableA ( ID, SUB_ID, Value ) AS
          SELECT 100, 1, 100 FROM DUAL
UNION ALL SELECT 100, 2, 150 FROM DUAL
UNION ALL SELECT 101, 1, 100 FROM DUAL
UNION ALL SELECT 101, 2, 150 FROM DUAL
UNION ALL SELECT 101, 3, 200 FROM DUAL
UNION ALL SELECT 102, 1, 100 FROM DUAL

查询 1：

WITH sub_ids AS (
  SELECT LEVEL AS sub_id
  FROM   DUAL
  CONNECT BY LEVEL <= ( SELECT MAX( SUB_ID ) FROM TableA )
),
max_values AS (
  SELECT ID,
         MAX( VALUE ) AS max_value
  FROM   TableA
  GROUP BY ID
)
SELECT s.SUB_ID,
       SUM( COALESCE( a.VALUE, m.max_value ) ) AS total_value
FROM   sub_ids s
       CROSS JOIN
       max_values m
       LEFT OUTER JOIN
       TableA a
       ON ( s.SUB_ID = a.SUB_ID AND m.ID = a.ID )
GROUP BY
       s.SUB_ID

Results：

| SUB_ID | TOTAL_VALUE |
|--------|-------------|
|      1 |         300 |
|      2 |         400 |
|      3 |         450 |

Answer 2

试试这个

SELECT SUB_ID,SUM(values),
 (SELECT DISTINCT SUBSTRING(   
(   
SELECT '+'+ CAST(values AS VARCHAR)
  FROM table_Name  AS T2  
WHERE T2.SUB_ID = d.SUB_ID        
 FOR XML PATH ('') 
),2,100000)[values]) as values  
FROm table_Name d
GROUP BY SUB_ID

Answer 3

这样的事情怎么样：

select max_vals.sub_id, sum(nvl(table_vals.value,max_vals.max_value)) as sum_values
from (
    select all_subs.sub_id, t1.id, max(t1.value) as max_value
    from your_table t1
    cross join (select sub_id from your_table) all_subs
    group by all_subs.sub_id, t1.id
) max_vals
left outer join your_table table_vals
on max_vals.id = table_vals.id
and max_vals.sub_id = table_vals.sub_id
group by max_vals.sub_id;

内部查询为您提供所有 sub_id/id 组合及其备用值的列表。 out 查询使用nvl 来使用表值（如果存在），如果不存在则使用备用值。