【发布时间】:2013-10-16 07:07:59
【问题描述】:
我有 2 个表来指示对象的状态何时有效。我需要加入/合并/联合它们,这样我就可以在一张表中知道在任何给定更改时两个状态是什么。
表1:
Object status1 date
Obj1 Open 1998-01-01 00:00:00.000
Obj1 Closed 2000-06-01 00:00:00.000
Obj1 Open 2008-03-06 00:00:00.000
Obj1 Closed 2013-01-01 00:00:00.000
表2:
Object status2 date
Obj1 ACTIVE 1999-01-01 00:00:00.000
Obj1 INACTIV 2000-08-29 00:00:00.000
Obj1 UNKNOWN 2004-05-06 00:00:00.000
Obj1 check 2014-05-01 00:00:00.000
结果我需要这样的东西:
Object status1 status2 date
Obj1 Open NULL 1998-01-01 00:00:00.000
Obj1 Open ACTIVE 1999-01-01 00:00:00.000
Obj1 Closed ACTIVE 2000-06-01 00:00:00.000
Obj1 Closed INACTIV 2000-08-29 00:00:00.000
Obj1 Closed UNKNOWN 2004-05-06 00:00:00.000
Obj1 Open UNKNOWN 2008-03-06 00:00:00.000
Obj1 Closed UNKNOWN 2013-01-01 00:00:00.000
Obj1 Closed check 2014-05-01 00:00:00.000
这里是创建源表的脚本:
CREATE TABLE [dbo].[table2](
[Object] [nvarchar](1000) NULL,
[status2] [nvarchar](1000) NULL,
[date] [datetime] NULL
) ON [PRIMARY]
GO
INSERT [dbo].[table2] ([Object], [status2], [date]) VALUES (N'Obj1', N'ACTIVE', CAST(0x00008D3F00000000 AS DateTime))
INSERT [dbo].[table2] ([Object], [status2], [date]) VALUES (N'Obj1', N'INACTIV', CAST(0x00008F9D00000000 AS DateTime))
INSERT [dbo].[table2] ([Object], [status2], [date]) VALUES (N'Obj1', N'UNKNOWN', CAST(0x000094DF00000000 AS DateTime))
INSERT [dbo].[table2] ([Object], [status2], [date]) VALUES (N'Obj1', N'check', CAST(0x0000A31E00000000 AS DateTime))
go
CREATE TABLE [dbo].[table1](
[Object] [nvarchar](1000) NULL,
[status1] [nvarchar](1000) NULL,
[date] [datetime] NULL
) ON [PRIMARY]
GO
INSERT [dbo].[table1] ([Object], [status1], [date]) VALUES (N'Obj1', N'Open', CAST(0x00008BD200000000 AS DateTime))
INSERT [dbo].[table1] ([Object], [status1], [date]) VALUES (N'Obj1', N'Closed', CAST(0x00008F4400000000 AS DateTime))
INSERT [dbo].[table1] ([Object], [status1], [date]) VALUES (N'Obj1', N'Open', CAST(0x00009A5700000000 AS DateTime))
INSERT [dbo].[table1] ([Object], [status1], [date]) VALUES (N'Obj1', N'Closed', CAST(0x0000A13900000000 AS DateTime))
有人有想法吗? 托梅克
【问题讨论】:
-
为您的特定示例创建表格和数据的出色脚本。 +1
标签: sql sql-server tsql