collect function 创建一个嵌套表,在您的情况下是一个字符串表,然后您将其转换为特定类型 - 即定义为 varchar2 表的类型。您不能转换为单个字符串。
有一些众所周知的字符串聚合技术列表,like this one。有一个that uses collect,但你仍然需要表格类型和一个函数来将生成的表格转换为分隔字符串。
逐字复制该示例:
CREATE OR REPLACE TYPE t_varchar2_tab AS TABLE OF VARCHAR2(4000);
/
CREATE OR REPLACE FUNCTION tab_to_string (p_varchar2_tab IN t_varchar2_tab,
p_delimiter IN VARCHAR2 DEFAULT ',') RETURN VARCHAR2 IS
l_string VARCHAR2(32767);
BEGIN
FOR i IN p_varchar2_tab.FIRST .. p_varchar2_tab.LAST LOOP
IF i != p_varchar2_tab.FIRST THEN
l_string := l_string || p_delimiter;
END IF;
l_string := l_string || p_varchar2_tab(i);
END LOOP;
RETURN l_string;
END tab_to_string;
/
使用该类型和功能,您可以:
SELECT tab_to_string(CAST(COLLECT(DISTINCT lot) AS t_varchar2_tab)) AS lot FROM ...
有趣的是,the 10g version of collect 不支持DISTINCT;它不会抱怨(!?),但会留下重复。
您可以通过the set function 传递集合以删除重复项:
SELECT tab_to_string(SET(CAST(COLLECT(DISTINCT lot) AS t_varchar2_tab))) AS lot FROM ...
在 10.2.0.5 中运行快速演示:
create table table1(order_no number, lot varchar2(10));
insert into table1 values (590288, '2016538');
insert into table1 values (590288, '2016535');
insert into table1 values (590288, '6016535');
insert into table1 values (590288, '2016535');
insert into table1 values (590288, '2016538');
SELECT order_no, tab_to_string(SET(CAST(COLLECT(DISTINCT lot) AS t_varchar2_tab))) AS LOT
FROM table1 WHERE order_no = 590288 GROUP BY order_no;
ORDER_NO LOT
---------- --------------------------------------------------
590288 2016538,2016535,6016535