从 SQL 表创建 XML - 如何从 XML 结构中删除不需要的标签？

Question

我有一个表tmpZstock 有两列：ZART_Article Code（项目代码）和GERNR_SerialNO（序列号）：

CREATE TABLE tmpZstock (
    [ZART_Article Code] INT,
    GERNR_SerialNO INT
)

INSERT INTO tmpZstock ([ZART_Article Code], GERNR_SerialNO)
VALUES  (200078, 126),
        (200078, 127),
        (200078, 128),
        (200078, 129),
        (200078, 130),
        (200079, 131),
        (200079, 132),
        (200079, 133),
        (200079, 134),
        (200079, 135),
        (200079, 136),
        (200079, 137),
        (200079, 138),
        (200079, 139),
        (200079, 140),
        (200079, 141),
        (200080, 142),
        (200080, 143),
        (200080, 144),
        (200080, 145)

我需要像这样创建 xml：

但是当我写这个查询时：

Select [ZART_Article Code] as ITEMCODE ,
(
Select SERIALS.[GERNR_SerialNO]  as SERIALNO From tmpZstock SERIALS  
where SERIALS.[ZART_Article Code]=T1.[ZART_Article Code] FOR   XML rAW ('SERIALS'), TYPE )
From (select [ZART_Article Code] from tmpZstock group by [ZART_Article Code]) t1  FOR   XML PATH('SERIALNUMBERDETAILS'), TYPE
,Root ('SUMMARY')

结果是：

我不需要<SERIALS> 标签 - 我如何从结果中消除这个标签？

Answer 1

您可以改为使用 xml 路径。应该这样做。

select T1.[ZART_Article Code] as ITEMCODE,
       (
       select T2.GERNR_SerialNO as SERIALNO
       from tmpZstock as T2
       where T1.[ZART_Article Code] = T2.[ZART_Article Code]
       for xml path(''), type
       )
from tmpZstock as T1
group by T1.[ZART_Article Code]
for xml path('SERIALNUMBERDETAILS'), root('SUMMARY')

带有表变量的工作示例。

declare @T table
(
  [ZART_Article Code] int,
  GERNR_SerialNO  int
);

insert into @T values
(200078, 126),
(200078, 127),
(200078, 128),
(200078, 129),
(200078, 130),
(200079, 131),
(200079, 132),
(200079, 133),
(200079, 134),
(200079, 135),
(200079, 136),
(200079, 137),
(200079, 138),
(200079, 139),
(200079, 140),
(200079, 141),
(200080, 142),
(200080, 143),
(200080, 144),
(200080, 145);

select T1.[ZART_Article Code] as ITEMCODE,
       (
       select T2.GERNR_SerialNO as SERIALNO
       from @T as T2
       where T1.[ZART_Article Code] = T2.[ZART_Article Code]
       for xml path(''), type
       )
from @T as T1
group by T1.[ZART_Article Code]
for xml path('SERIALNUMBERDETAILS'), root('SUMMARY')

结果：

<SUMMARY>
  <SERIALNUMBERDETAILS>
    <ITEMCODE>200078</ITEMCODE>
    <SERIALNO>126</SERIALNO>
    <SERIALNO>127</SERIALNO>
    <SERIALNO>128</SERIALNO>
    <SERIALNO>129</SERIALNO>
    <SERIALNO>130</SERIALNO>
  </SERIALNUMBERDETAILS>
  <SERIALNUMBERDETAILS>
    <ITEMCODE>200079</ITEMCODE>
    <SERIALNO>131</SERIALNO>
    <SERIALNO>132</SERIALNO>
    <SERIALNO>133</SERIALNO>
    <SERIALNO>134</SERIALNO>
    <SERIALNO>135</SERIALNO>
    <SERIALNO>136</SERIALNO>
    <SERIALNO>137</SERIALNO>
    <SERIALNO>138</SERIALNO>
    <SERIALNO>139</SERIALNO>
    <SERIALNO>140</SERIALNO>
    <SERIALNO>141</SERIALNO>
  </SERIALNUMBERDETAILS>
  <SERIALNUMBERDETAILS>
    <ITEMCODE>200080</ITEMCODE>
    <SERIALNO>142</SERIALNO>
    <SERIALNO>143</SERIALNO>
    <SERIALNO>144</SERIALNO>
    <SERIALNO>145</SERIALNO>
  </SERIALNUMBERDETAILS>
</SUMMARY>