将值添加到sql server中的单个列中答案

【问题标题】：Add values show into single column in sql server将值添加到sql server中的单个列中
【发布时间】：2013-04-20 10:54:22
【问题描述】：

在我的表中，我有类似的经验字段

经验

5Years0Months
2Years0Months

在这里我想转换成秒，然后将年份和月份添加到单个列中。

经验 - [一些价值]

所以我创建了一个如下查询，

select top(10)'insert into candidates(experience)values('+

CAST(SUBSTRING(CAST(o.Experience AS VARCHAR(50)), 0, PATINDEX('%Years%', o.Experience))      * 31536000 AS VARCHAR(50))

           +','+CAST(SUBSTRING(CAST(o.Experience AS VARCHAR(50)), PATINDEX('%Years%', o.Experience) + 5

        ,patindex('%Months%', o.Experience) - PATINDEX('%Years%', o.Experience) - 5) * 
2678400 AS VARCHAR(50))+')'

            from candidatedetails as o

从上面的代码我得到的结果是，

经验

insert into candidates(experience)values(157680000,0)
insert into candidates(experience)values(31536000,26784000)

预期结果

 insert into candidates(experience)values(157680000)
 insert into candidates(experience)values(58320000)//add(31536000+26784000)

如何在我的查询中做到这一点？有人帮帮我吗？

【问题讨论】：

标签： sql-server sql-server-2008 select patindex

【解决方案1】：

你想要的是变成这样的东西（当前生成的）

insert into candidates(experience)values(157680000,0)
insert into candidates(experience)values(31536000,26784000)

到此，将它们相加

insert into candidates(experience) select 157680000+0;
insert into candidates(experience) select 31536000+26784000;

这看起来像是在更改您的原始代码：

select top(10) 'insert into candidates(experience) select '+
        CAST(SUBSTRING(CAST(o.Experience AS VARCHAR(50)), 0,
             PATINDEX('%Years%', o.Experience)) * 31536000 AS VARCHAR(50))
   +'+'+CAST(SUBSTRING(CAST(o.Experience AS VARCHAR(50)),
             PATINDEX('%Years%', o.Experience) + 5,
             patindex('%Months%', o.Experience)
           - PATINDEX('%Years%', o.Experience) - 5) * 2678400 AS VARCHAR(50))+';'
from candidatedetails as o

【讨论】：

【解决方案2】：

我找到了答案，

SELECT TOP(10) 'INSERT INTO jobs(Experience) VALUES('+
        CAST(SUBSTRING(CAST(r.experience AS VARCHAR(50)), 0, PATINDEX('%Years%', r.experience))*31536000
            + SUBSTRING(CAST(r.experience AS VARCHAR(50)), PATINDEX('%Years%', r.experience) + 5, 
                                                       patindex('%Months%', r.Experience) - PATINDEX('%Years%', r.Experience) - 5)* 2678400 AS VARCHAR(50))+')'
    FROM  candidatedetails r

【讨论】：