日期问题 SQL 每月第一天交叉答案

【问题标题】：Date issues SQL first day of month crossover日期问题 SQL 每月第一天交叉
【发布时间】：2015-08-14 07:42:02
【问题描述】：

这是我第 27 年的问题周显示 2 个日期，因为该月的交叉发生它会生成另一个月的第一天日期，我只想在每个发生这种情况的情况下向第一次约会展示

日期时间----------------|WeekofYear ------|FirstDayOfMonth 2015-06-29 00:00:00.000 |27 --------------|2015-06-01 00:00:00.000 2015-07-01 00:00:00.000 |27 --------------|2015-07-01 00:00:00.000

CREATE TABLE #weekonweek
(
[Datetime] datetime,
[WeekofYear] int,
[FirstDayOfMonth] datetime
)

INSERT INTO #weekonweek

SELECT 
min(c.Datetime),
c.WeekOfYear
,c.FirstDayOfMonth

FROM Calendar c
WHERE YEAR = 2015
and WeekOfYear = 27
GROUP BY WeekOfYear ,c.FirstDayOfMonth
SELECT * FROM #weekonweek


CREATE TABLE #subtable
(
[Datetime] datetime,
[WeekofYear] int,
[FirstDayOfMonth] datetime,
)

INSERT INTO #subtable

SELECT 
c.Datetime,
w.WeekOfYear,
min(w.FirstdayofMonth)
FROM Calendar c
LEFT JOIN #weekonweek w on c.WeekOfYear  = w.WeekofYear
WHERE YEAR = 2015
and c.WeekOfYear = 27
and w.FirstDayOfMonth <w.FirstDayOfMonth
group by c.Datetime,
w.WeekOfYear
SELECT * FROM #subtable
DROP TABLE #subtable
DROP TABLE #weekonweek

【问题讨论】：

请添加日历表结构..
@AbhayChauhan im 700 个字符的结构太多了
为清楚起见，提供所需的输出。
日期时间日期ShortDate FullDate DAYOFMONTH DaySuffix DAYNAME DAYOFWEEK DayOfWeekInMonth DayOfWeekInYear DayOfQuarter DAYOFYEAR WEEKOFYEAR月MONTHNAME MonthOfQuarter季QuarterName年份YEARWEEK MonthYear时期Firstdayofweek可LastDayOfWeek FirstDayOfLastWeek LastDayOfLastWeek FirstDayOfMonth LastDayOfMonth FirstDayOfLastMonth LastDayOfLastMonth FirstDayOfQuarter LastDayOfQuarter FirstDayOfYear LastDayOfYear IsWeekday IsEnglishHoliday EnglishHoliday WeeklyPeriod 跨度>
日期时间----------------|WeekofYear ------|FirstDayOfMonth 2015-06-29 00:00:00.000 |27 --- -----------|2015-06-01 00:00:00.000

标签： sql-server datetime

【解决方案1】：

所以如果你想实现这个输出：

Datetime----------------|WeekofYear------|FirstDayOfMonth 
2015-06-29 00:00:00.000 |27--------------|2015-06-01 00:00:00.000

您只需使用TOP 1 并添加ORDER BY 子句。

SELECT TOP 1 * -- like this
FROM #subtable
ORDER BY DateTime -- here you need to pass ORDER BY

【讨论】：

【解决方案2】：

SELECT DR.DivNo
    ,p.[ProductCode]
    ,p.ProductClass
    ,p.EmpNo
    ,[Description]
    ,[CGNo]
    ,[SCGNo]
    ,dr.Retail
    ,bd.[Buying Director]
INTO #Product
FROM [PRODUCT] p
LEFT JOIN [DIVRETAIL] DR ON p.ProductCode = DR.ProductCode
WHERE dr.ValidTo IS NULL
    AND dr.DivNo NOT LIKE '8__'
GROUP BY DR.DivNo
    ,p.[ProductCode]
    ,p.ProductClass
    ,p.EmpNo
    ,bd.[Buying Director]
    ,[Description]
    ,[CGNo]
    ,[SCGNo]
    ,dr.Retail



SELECT TOP 1000 [Datetime]
        ,[FirstDayOfWeek]
        ,[FirstDayOfMonth]
        ,s.NoOfStores
        ,s.DivNo
    INTO #stores
    FROM [Calendar] c
    LEFT JOIN Stores s ON c.FirstDayOfMonth = s.Validfrom
    WHERE DATETIME = firstdayofweek

【讨论】：