有什么办法可以使这种情况起作用吗？

Question

这是我的桌子：

DATE        |BRANCH   |DESC
2019-12-25  |ALL      |Christmas Day
2019-12-25  |HO       |Christmas Day
2019-12-25  |TES      |Christmas Day

这是我的查询：

DECLARE 
@APPTDATE Datetime = '2019-12-25',
@BRANCHCODE varchar(50) = 'HO'

SELECT *
FROM TABLE_NAME
WHERE CAST([DATE] AS DATE) = CAST(@APPTDATE AS DATE) AND ((BRANCH = @BRANCHCODE) OR (BRANCH != @BRANCHCODE AND BRANCH = 'ALL'))

结果：

DATE        |BRANCH   |DESC
2019-12-25  |ALL      |Christmas Day
2019-12-25  |HO       |Christmas Day

这是我想要的结果；

如果 ([BRANCH] = HO) 我只需要显示具有 [BRANCH] = "HO" 的 [DESC]；

DATE        |BRANCH   |DESC
2019-12-25  |HO       |Christmas Day

或者如果[BRANCH]的值在表中不存在但指定的日期在数据库中存在；

DATE        |BRANCH   |DESC
2019-12-25  |ALL      |Christmas Day

编辑：

所以如果 BRANCH = HO 并且 DATE = '2019-12-25' 并且表格是：

DATE        |BRANCH   |DESC
2019-12-25  |ALL      |Christmas Day (1)
2019-12-25  |TES      |Christmas Day (2)

由于分支列表中不存在 HO 但日期确实存在，因此输出应为：

DATE        |BRANCH   |DESC
2019-12-25  |ALL      |Christmas Day (1)

因为 ALL = 表示只要日期条件为真的任何分支。

是否可以使用我的 where 语句中的条件来实现结果，或者有更好的方法来执行这样的结果？

Answer 1

如果你知道你想要后排，你可以使用order by和top：

SELECT TOP (1) t.*
FROM TABLE_NAME t
WHERE CAST([DATE] AS DATE) = CAST(@APPTDATE AS DATE) AND 
      BRANCH IN ('ALL', @BRANCHCODE) 
ORDER BY (CASE WHEN BRANCHE = @BRANCHCODE THEN 1 ELSE 2 END);

这只会选择所需的分支和'ALL'。然后顺序将它们与所需的第一个顺序排列在一起，TOP (1) 选择先到的那个。

Answer 2

在这两种情况下使用UNION ALL：

DECLARE 
@APPTDATE Datetime = '2019-12-25',
@BRANCHCODE varchar(50) = 'HO'

SELECT * FROM TABLE_NAME
WHERE [BRANCH] = @BRANCHCODE
UNION ALL
SELECT * FROM TABLE_NAME
WHERE CAST([DATE] AS DATE) = CAST(@APPTDATE AS DATE) AND [BRANCH] = 'ALL'
AND NOT EXISTS (
  SELECT 1 FROM TABLE_NAME
  WHERE [BRANCH] = @BRANCHCODE
)

请参阅demo。

Answer 3

IF EXISTS (SELECT branch FROM table where branch = @BRANCHCODE)
    BEGIN
        SELECT * FROM table where branch = @branchcode
    END
ELSE
    BEGIN
        SELECT * FROM table WHERE CAST([DATE] AS DATE) = CAST(@APPTDATE AS DATE)
    END

这两个可能是解决方案。尚未在架构上对其进行测试。希望对您有所帮助。

SELECT * FROM Table 
WHERE
 1= CASE WHEN branch = @branchCode THEN 1 
 ELSE CASE WHEN CAST([DATE] AS DATE) = CAST(@APPTDATE AS DATE) AND branch != @branchcode THEN 1 ELSE 0 END END 

Answer 4

你可以试试下面这个脚本-

DECLARE @APPTDATE DATETIME= '2019-12-25', 
    @BRANCHCODE VARCHAR(50)= 'HO';

SELECT *
FROM TABLE_NAME
WHERE BRANCH = @BRANCHCODE
OR(
    BRANCH <> @BRANCHCODE
    AND CAST([DATE] AS DATE) = CAST(@APPTDATE AS DATE)
)

更新：

SELECT *
FROM your_table
WHERE BRANCH = @BRANCHCODE
OR(
    BRANCH ='ALL'
    AND CAST([DATE] AS DATE) = CAST(@APPTDATE AS DATE)
)