如何将值从另一个表插入到一个表中答案

【问题标题】：How to insert values into one table from another table如何将值从另一个表插入到一个表中
【发布时间】：2015-07-30 09:59:54
【问题描述】：

我有两个表，即table1 和table2，结构相同，我想将 table1 的所有值插入 table2。这些表包含两个图像类型列。我试过这个查询，但没有成功。

DECLARE @imagepan VARBINARY(MAX)
DECLARE @imagecheque VARBINARY(MAX)

SET @imagepan=(SELECT panid FROM table1 WHERE Emp_code='E001')
SET @imagecheque=(SELECT cancel_checqe FROM table1 WHERE Emp_code='E001')
INSERT INTO table2 
    (transno, Emp_code, PanNo, panid, panext, entdt_pan, banknm, 
    cancel_checqe, chqExt, entDt_bnk, Acc_No, IFSC, Cheque_nm, status_pan1, 
    status_pan, status_bnk1, status_bnk, userid, entdt, panModify_by, 
    panModify_on, bnkModify_by, bnkModify_on) 
VALUES
    (SELECT 
        transno, Emp_code, PanNo, @imagepan, panext, entdt_pan, 
        banknm, @imagecheque, chqExt, entDt_bnk, Acc_No, IFSC, Cheque_nm, 
        status_pan1, status_pan, status_bnk1, status_bnk, userid, entdt, 
        panModify_by, panModify_on, bnkModify_by, bnkModify_on 
    FROM 
        table1 
    WHERE 
        Emp_code='E001')

我怎样才能做到这一点？

【问题讨论】：

INSERT INTO table1 (CustomerName, Country) SELECT SupplierName, Country FROM table2 从您的代码中删除 values (

标签： sql sql-server

【解决方案1】：

删除“值”关键字

insert into table2 (transno, Emp_code, PanNo, panid, panext, entdt_pan, 
                    banknm, cancel_checqe, chqExt, entDt_bnk, Acc_No, 
                    IFSC, Cheque_nm, status_pan1, status_pan, 
                    status_bnk1, status_bnk, userid, entdt, panModify_by, 
                    panModify_on, bnkModify_by, bnkModify_on) 
    select 
        transno, Emp_code, PanNo, @imagepan, panext, entdt_pan, 
        banknm, @imagecheque, chqExt, entDt_bnk, Acc_No, 
        IFSC, Cheque_nm, status_pan1, status_pan, 
        status_bnk1, status_bnk, userid, entdt, panModify_by, 
        panModify_on, bnkModify_by, bnkModify_on 
    from 
        table1 
    where 
        Emp_code = 'E001';

【讨论】：

【解决方案2】：

只需删除values ( 并在最后关闭)：

DECLARE @imagepan VARBINARY(MAX);
DECLARE @imagecheque VARBINARY(MAX);

SET @imagepan = (SELECT panid FROM table1 WHERE Emp_code = 'E001');
SET @imagecheque = (SELECT cancel_checqe FROM table1 WHERE Emp_code = 'E001');

INSERT INTO table2 (transno, Emp_code, PanNo, panid, panext, entdt_pan, 
banknm, cancel_checqe, chqExt, entDt_bnk, Acc_No, IFSC, Cheque_nm, 
status_pan1, status_pan, status_bnk1, status_bnk, userid, entdt, 
panModify_by, panModify_on, bnkModify_by, bnkModify_on) 
SELECT transno, Emp_code, PanNo, @imagepan, panext, entdt_pan, 
banknm, @imagecheque, chqExt, entDt_bnk, Acc_No, IFSC, Cheque_nm, 
status_pan1, status_pan, status_bnk1, status_bnk, userid, entdt, 
panModify_by, panModify_on, bnkModify_by, bnkModify_on 
FROM table1 
WHERE Emp_code='E001';

【讨论】：