如何在 PLSQL 中过滤 json？答案

【问题标题】：How to filter json in PLSQL?如何在 PLSQL 中过滤 json？
【发布时间】：2020-12-14 10:18:14
【问题描述】：

我的数据如下：

CLUID                       EVENT_PAYLOAD                                                       STEP    
1998-06-22-23.58.16.792243  {"type":"page","name":"currentAccount/88095C45B7E1D68346905AA7B791F731D7F94715/new-transfer","source":"currentAccount/:id/new-transfer","data":{}}  currentAccount/:id/new-transfer
1997-08-25-18.52.07.994112  {"type":"page","name":"orders/sign/200831527425199","source":"orders/sign(/:orderIds)","data":{}}   orders/sign(/:orderIds)
2000-05-09-20.49.42.573031  {"type":"page","name":"currentAccount/33BF3B031E71719AD30C34588B5832CA8F1EC2D1/orders","source":"currentAccount/:id/orders","data":{}}  currentAccount/:id/orders
1998-07-21-20.50.04.641225  {"type":"event","name":"logout","source":"currentAccount/F2A81A2D982AD8D736E5461808CF8C33FDDC9EEC/transactions","data":{"category":"session","normalized":"currentAccount/:id/transactions","eventValue1":"manual"}}    logout

我只想选择 EVENT_PAYLOAD 类型为“页面”的数据。

我写过：

 SELECT CLUID, STEP--, b.type
 FROM VDS_OWNER.PROTO_BEAN_COUNTER_EVENTS_BASE2
 WHERE (JSON_TABLE(EVENT_PAYLOAD, '$'
                        COLUMNS (type VARCHAR2 PATH '$."type"')
                        )
        ) = 'page'

我们将不胜感激。谢谢！

【问题讨论】：

标签： sql json oracle plsql

【解决方案1】：

如果你已经正确声明了 JSON 列，你可以使用点符号来按键访问 JSON 值：

select cluid, step, e.event_payload.type
from VDS_OWNER.PROTO_BEAN_COUNTER_EVENTS_BASE2 e
where e.event_payload.type = 'page'

或者，您可以使用json_value()：

select cluid, step, json_value(e.event_payload, '$.type') as type
from mytable e
where json_value(e.event_payload, '$.type') = 'page'

Demo on DB Fiddle

【讨论】：