Mysql 命令未正确结束

Question

我在试图找出错误所在的位置时遇到了麻烦。据我所知，一切看起来都是正确的：

SELECT  a.department_name
FROM department a
OUTER JOIN (SELECT department_id, 
            NVL((TO_CHAR(MAX(salary + commission)), '$9,990.00'), '$0.00') as "Maximum Total Pay",
            NVL((TO_CHAR(MAX(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Maximum Hire Date",
            NVL((TO_CHAR(MIN(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Minimum Hire Date",
            COUNT(*) AS NUMBER_OF_EMPLOYEES
            FROM employee c
            WHERE employee_id IS NOT NULL
            GROUP BY c.department_id)
ON          a.department_id = c.department_id  
ORDER BY    a.department_name;

我收到 SQL 命令未正确结束的错误。任何帮助将不胜感激。

谢谢！

编辑：我无法选择两个正确答案，因为这两个答案都帮助我找到了正确的解决方案。感谢所有帮助过的人。

Answer 1

我想，空值可能来自您的子查询，但不是来自部门，所以使用LEFT OUTER JOIN。

但主要问题是由于括号

NVL((TO_CHAR(MAX(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') 语句，

两用：

NVL(TO_CHAR(MAX(hire_date), 'DD-MON-YYYY'), '01-JAN-3000') 改为从左侧删除第 1 个和第 5 个括号。

Answer 2

看来您需要为要加入的子查询添加别名，并添加关键字LEFT：

SELECT  a.department_name
FROM department a
LEFT OUTER JOIN (SELECT department_id, 
            NVL((TO_CHAR(MAX(salary + commission)), '$9,990.00'), '$0.00') as "Maximum Total Pay",
            NVL((TO_CHAR(MAX(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Maximum Hire Date",
            NVL((TO_CHAR(MIN(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Minimum Hire Date",
            COUNT(*) AS NUMBER_OF_EMPLOYEES
            FROM employee c
            WHERE employee_id IS NOT NULL
            GROUP BY c.department_id) c1
ON          a.department_id = c1.department_id  
ORDER BY    a.department_name;

我称它为 c1 只是为了让您注意到别名。