来自两个表的 MYSQL QUERY 总和答案

【问题标题】：MYSQL QUERY sum from two tables来自两个表的 MYSQL QUERY 总和
【发布时间】：2011-11-06 14:30:55
【问题描述】：

嘿，我在下面的 Mysql 查询中遇到了一些问题，我如何从 team_stats 表而不是 driver_stats 表中计算 SUMS（计算点，查询中的第 5 和第 6 和）与现在 team_id = 3 的条件相同。我所需要的只是将这些计算从 driver_stats 表交换到 team_stats 表，我遇到的问题是，当我尝试这样做时，计算就像它一样高不是只为 where team_id = '3' 或任何数字做这些。

任何帮助将非常感谢。

SELECT       t.teamname,
             t.value,
             SUM(IF(qual_pos = '1', 1,0)) AS poles,
             SUM(IF(race_pos <= '3', 1,0)) AS podiums,
             SUM(IF(race_pos = '1', 1,0)) AS victories,
             SUM(overtakes) AS overtakes,
             SUM(CASE
               WHEN s.track_id = (SELECT MAX(track_id) FROM driver_stats) THEN
                 points
               ELSE
                 0
             End) AS lastracepoints,

             # CHANGE THIS SUM AND THE SUM ABOVE TO CALCULATE
             # the points column in the tale named TEAM_STATS
             # but with the same restrictions as now,
             # only where team_id = 3
             SUM(points) AS points 

FROM         driver_stats s
  LEFT JOIN  drivers d
  ON         d.drivers_id = s.drivers_id
  LEFT JOIN  teams t
  ON         d.team_id = t.team_id
WHERE        d.team_id = 3

【问题讨论】：

标签： mysql sql

【解决方案1】：

在特殊情况下，MySQL 可以让您使用聚合（sum）而不定义 group by 子句，但这不是典型的，对您不起作用。

Is it possible to use Aggregate function in a Select statment without using Group By clause?

我没有通过 try 测试过这个：

SELECT       t.teamname,
             t.value,
             SUM(IF(qual_pos = '1', 1,0)) AS poles,
             SUM(IF(race_pos <= '3', 1,0)) AS podiums,
             SUM(IF(race_pos = '1', 1,0)) AS victories,
             SUM(overtakes) AS overtakes,
             SUM(CASE
               WHEN s.track_id = (SELECT MAX(track_id) FROM driver_stats) THEN
                 points
               ELSE
                 0
             End) AS lastracepoints,
             SUM(points) AS points 

FROM         drivers d
  INNER JOIN  driver_stats s
  ON         d.drivers_id = s.drivers_id
  AND         d.team_id = 3
  LEFT JOIN  teams t
  ON         d.team_id = t.team_id
GROUP BY
    teamname,
    `value`

【讨论】：