【发布时间】:2017-04-08 09:18:42
【问题描述】:
我有employeeinfo 表和employeeloan 表.. 我使用这个查询:
$result=mysqli_query($con,"select tblemployeeinfo.employeeid, tblemployeeloan.amount from tblemployeeinfo left join tblemployeeloan on tblemployeeinfo.employeeid = tblemployeeloan.employeeid where tblemployeeinfo.employeeid = <employee id for example employee id 1>");
while($row = mysqli_fetch_array($result)){
echo "<br>".$row['employeeid'];
echo "<br>".$row['amount'];
}
结果是
employee id: 1
amount: 1000
employee id: 1
amount: 500
employee id: 1
amount: 100
但我想要的是这样显示:
employee id: 1
amount: 1000
amount: 500
amount: 100
抱歉我的英语不好。提前 tnx
【问题讨论】:
-
你确定你的结果有员工 id 吗?我没有看到您在查询中选择了它
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对不起,先生...我不好,我会编辑我的帖子..据说那是 tblemployeeid.employeeid
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你可能需要做“order by”,因为查询是join,你需要删除重复的。