【问题标题】:Converting a CTE query to SQLAlchemy ORM将 CTE 查询转换为 SQLAlchemy ORM
【发布时间】:2020-10-14 18:16:52
【问题描述】:

(这是今天早些时候删除的问题的重写版本。)

我使用 SQLAlchemy ORM 作为 Flask 应用程序的一部分,使用 MySQL 作为后端,我正在尝试编写一个查询以返回围绕特定条目的条目列表。虽然我在 SQL 中有一个有效的查询,但我不确定如何在 SQLA 中对其进行编码。 docs for CTE in the ORM 给出了一个非常复杂的例子,其他的例子我找不到了。

现在假设一个非常简单的表,只包含单词:

class Word(db.Model):
    __tablename__ = 'word'
    id = db.Column(db.Integer, primary_key=True)
    word = db.Column(db.String(100))

如果我想要给定单词之前和之后的 10 个单词(id 为 73),那么满足我需要的 SQL 查询是:

WITH cte AS (SELECT id, word, ROW_NUMBER() OVER (ORDER BY word) AS rownumber FROM word)
SELECT * FROM cte
WHERE rownumber > (SELECT rownumber FROM cte WHERE cte.id = 73) - 10
AND rownumber < (SELECT rownumber FROM cte WHERE cte.id = 73) + 10
ORDER BY rownumber;

但是,我无法弄清楚下一步。我想获取 Word 对象的列表。我想它的第一部分可能是这样的

id = 73
rowlist = db.session.query(Word.id, db.func.row_number()).filter(Word.id == id).order_by(Word.word).cte()

但即使这是正确的,我也不知道如何将它带入下一部分;我陷入了示例中的aliased 位。有人可以推动我朝着正确的方向前进吗?

【问题讨论】:

    标签: python sql sqlalchemy


    【解决方案1】:

    这可能不是最优雅的解决方案,但它似乎对我有用:

    engine = db.create_engine(sqlalchemy_uri)
    
    Base = declarative_base()
    
    
    class Word(Base):
        __tablename__ = "so64359277"
        id = db.Column(db.Integer, primary_key=True)
        word = db.Column(db.String(100))
    
        def __repr__(self):
            return f"<Word(id={self.id}, word='{self.word}')>"
    
    
    Base.metadata.drop_all(engine, checkfirst=True)
    Base.metadata.create_all(engine)
    Session = sessionmaker(bind=engine)
    session = Session()
    
    # test data
    word_objects = []
    for x in [
        "Hotel",
        "Charlie",
        "Alfa",
        "India",
        "Foxtrot",
        "Echo",
        "Bravo",
        "Golf",
        "Delta",
    ]:
        word_objects.append(Word(word=x))
    session.add_all(word_objects)
    session.commit()
    # show test data with id values
    pprint(session.query(Word).all())
    """console output:
    [<Word(id=1, word='Hotel')>,
     <Word(id=2, word='Charlie')>,
     <Word(id=3, word='Alfa')>,
     <Word(id=4, word='India')>,
     <Word(id=5, word='Foxtrot')>,
     <Word(id=6, word='Echo')>,
     <Word(id=7, word='Bravo')>,
     <Word(id=8, word='Golf')>,
     <Word(id=9, word='Delta')>]
    """
    
    target_word = "Echo"
    num_context_rows = 3
    
    rowlist = session.query(
        Word.id,
        Word.word,
        db.func.row_number().over(order_by=Word.word).label("rownum"),
    ).cte("rowlist")
    target_rownum = session.query(rowlist.c.rownum).filter(
        rowlist.c.word == target_word
    )
    select_subset = session.query(rowlist.c.rownum, rowlist.c.id).filter(
        db.and_(
            (rowlist.c.rownum >= target_rownum.scalar() - num_context_rows),
            (rowlist.c.rownum <= target_rownum.scalar() + num_context_rows),
        )
    )
    rownum_id_map = {x[0]: x[1] for x in select_subset.all()}
    min_rownum = min(rownum_id_map)
    max_rownum = max(rownum_id_map)
    result = []
    for rownum in range(min_rownum, max_rownum + 1):
        result.append(session.query(Word).get(rownum_id_map[rownum]))
    pprint(result)
    """console output:
    [<Word(id=7, word='Bravo')>,
     <Word(id=2, word='Charlie')>,
     <Word(id=9, word='Delta')>,
     <Word(id=6, word='Echo')>,
     <Word(id=5, word='Foxtrot')>,
     <Word(id=8, word='Golf')>]
     <Word(id=1, word='Hotel')>]
    """
    

    【讨论】:

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