正如@Chris Lively 所指出的,某种形式的可靠骆驼分割函数可能是最好的方法,但这里有一个查询可以内联。排序规则显然是模式匹配的一个考虑因素,在这种情况下,我在 PATINDEX 函数中使用了区分大小写的一个(顺便说一句,我必须在匹配表达式中明确定义每个大写字母,因为 [A-Z] 没有返回正确的结果,我认为这是another question....的主题)
CREATE TABLE dbo.OriginalNames
(
CamelCaseName VARCHAR(30),
)
GO
INSERT INTO dbo.OriginalNames VALUES ('thisIsColumnName')
INSERT INTO dbo.OriginalNames VALUES ('thisIsAttributeName')
INSERT INTO dbo.OriginalNames VALUES ('thisIsAnotherAttributeName')
GO
SELECT * FROM dbo.OriginalNames;
GO
WITH
L0 AS(SELECT 1 AS c UNION ALL SELECT 1),
L1 AS(SELECT 1 AS c FROM L0 AS A, L0 AS B),
L2 AS(SELECT 1 AS c FROM L1 AS A, L1 AS B),
L3 AS(SELECT 1 AS c FROM L2 AS A, L2 AS B),
Numbers AS(SELECT ROW_NUMBER() OVER(ORDER BY c) AS n FROM L3)
SELECT DISTINCT(SplitNames.Value)
FROM (
SELECT nums.n, names.CamelCaseName, LTRIM(RTRIM(SUBSTRING(names.CamelCaseName, nums.n - 1, PATINDEX('%[|ABCDEFGHIJKLMNOPQRSTUVWXYZ]%', SUBSTRING(names.CamelCaseName + N'|', nums.n, LEN(names.CamelCaseName)) COLLATE SQL_Latin1_General_Cp1_CS_AS)))) AS [Value]
FROM Numbers AS nums INNER JOIN dbo.OriginalNames AS names ON nums.n <= CONVERT(int, LEN(names.CamelCaseName) + 1) AND PATINDEX('%[|ABCDEFGHIJKLMNOPQRSTUVWXYZ]%', SUBSTRING(N'|' + names.CamelCaseName, nums.n, 1) COLLATE SQL_Latin1_General_Cp1_CS_AS) > 0) AS SplitNames
GO
--DROP TABLE dbo.OriginalNames
-- OUTPUT as follows
--
-- Value
-- =========
-- Another
-- Attribute
-- Column
-- Is
-- Name
-- this