【发布时间】:2019-11-25 11:04:34
【问题描述】:
我有两张表城市(如 C)和路线(如 R)
C:
____ ______
| id | city |
|____|______|
| 1 | A |
| 2 | B |
|____|______|
R:
____ ______ ____ __________
| id | from | to | distance |
|____|______|____|__________|
| 1 | 1 | 2 | 100 |
| 2 | 2 | 1 | 100 |
|____|______|____|__________|
(我的期望):我想将我的表格合并并加入以下表格:
____ ______ ____________ ____ __________ __________
| id | from | fromAsText | to | toAsText | distance |
|____|______|____________|____|__________|__________|
| 1 | 1 | A | 2 | B | 100 |
| 2 | 2 | B | 1 | A | 100 |
|____|______|____________|____|__________|__________|
添加一个值不是问题
SELECT
r.*
s.city as fromAsText
FROM
routes as r,
cities as s
WHERE
r.from = s.id
但我没有任何想法如何实现我的目标!谢谢!
【问题讨论】:
-
你确定你的预期结果正确吗?
-
请不要使用逗号分隔的连接。在标准 SQL 1992 中有冗余!改用显式连接:
FROM routes as r INNER JOIN cities as c ON c.id = r.from. -
Argh,出现错误,预期已更新