SQL 无法对包含聚合或子查询的表达式执行聚合函数答案

【问题标题】：SQL Cannot perform an aggregate function on an expression containing an aggregate or a subquerySQL 无法对包含聚合或子查询的表达式执行聚合函数
【发布时间】：2012-10-14 03:26:34
【问题描述】：

我是 SQL 新手，我有以下 SQL 查询

select catalogid, numitems, allitems - numitems ignoreditems
 from (
  select i.catalogid," 
    sum(case when (ocardtype in ('PayPal','Sofort') OR
                   ocardtype in ('mastercard','visa') and
                   odate is not null) AND NOT EXISTS (select CAST(booked AS INT) FROM bookedordersids b where b.booked = o.orderid)
                   then numitems
                   else 0 end) numitems,
    sum(numitems) allitems
  from orders o
  join oitems i on i.orderid=o.orderid
  group by i.catalogid
 ) X

它给了我以下错误

Cannot perform an aggregate function on an expression containing an aggregat or a subquery

当我删除以下行时，它工作正常

AND NOT EXISTS (select CAST(booked AS INT) FROM bookedordersids b where b.booked = o.orderid)

但是做这个检查很重要；我该如何解决这个问题？

【问题讨论】：

标签： sql select sql-server-2008-r2 case

【解决方案1】：

您可以将聚合移出一级。
虽然可以根据您的情况重写查询，但我认为最好以这种方式表达它，以便您可以轻松理解和重用该模式。

select catalogid, sum(numitems) numitems, sum(allitems) - sum(numitems) ignoreditems
 from (
  select i.catalogid,
    case when (ocardtype in ('PayPal','Sofort') OR
                   ocardtype in ('mastercard','visa') and
                   odate is not null) AND NOT EXISTS (
      select *
      FROM bookedordersids b
      where b.booked = o.orderid)
                   then numitems
                   else 0 end
    numitems,
    numitems allitems
  from orders o
  join oitems i on i.orderid=o.orderid
 ) X
group by catalogid

【讨论】：