我怎样才能得到这个表的递增数字？

Question

这是我的事件表。如何编写查询以添加列 X 当它在事件列中遇到 1 时递增

输入：

|id    |event|
|------|-----|
|1     |0    |
|2     |0    |
|3     |1    |
|4     |0    |
|5     |1    |
|6     |0    |
|7     |0    |
|8     |0    |
|9     |1    |
|10    |0    |

预期输出：

|id    |event| X |
|------|-----|---|
|1     |0    | 1 |
|2     |0    | 1 |
|3     |1    | 2 |
|4     |0    | 2 |
|5     |1    | 3 |
|6     |0    | 3 |
|7     |0    | 3 |
|8     |0    | 3 |
|9     |1    | 4 |
|10    |0    | 4 |

Answer 1

您只需要event 的累积总和：

select t.*,
       (sum(event) over (order by id) + 1) as x
from t;