【发布时间】:2009-06-15 15:56:18
【问题描述】:
在 MS Access 中,我有一些报告使用一些查询来显示某个日期范围内的数据。查询使用别名、if、sum 和 avg 函数,并连接多个表以获取其数据。
我想知道我是否可以使用 UNION ALL 以及包含所有必需字段的表来显示此表中的新数据以及旧数据,如果有人选择了跨越新的和旧的。
这是一个“旧”查询示例:
SELECT tblAssessment.fldValid, tblATraining.fldTID, tblATraining.fldTCrsID,
tblCourses.fldCrsName, [fldCrsHrs]/8 AS Days, tblATraining.fldTLocAbr,
tblDistrict.fldDistAbr, tblRegion.fldRegName, tblATraining.fldTDateStart,
tblATraining.fldTDateEnd, tblATraining.fldTEnrolled, tblATraining.fldTPID,
tblPersonnel.fldPName, tblAssessment.fldTrngSID, tblAssessment.Q1,
IIf([fldValid]=True,IIf([Q1]>0,1,0),0) AS Q1Valid, tblAssessment.Q2,
IIf([fldValid]=True,IIf([Q2]>0,1,0),0) AS Q2Valid, tblAssessment.Q3,
IIf([fldValid]=True,IIf([Q3]>0,1,0),0) AS Q3Valid, tblAssessment.Q4,
IIf([fldValid]=True,IIf([Q4]>0,1,0),0) AS Q4Valid, tblAssessment.Q5,
IIf([fldValid]=True,IIf([Q5]>0,1,0),0) AS Q5Valid, tblAssessment.Q6,
IIf([fldValid]=True,IIf([Q6]>0,1,0),0) AS Q6Valid, tblAssessment.Q7,
IIf([fldValid]=True,IIf([Q7]>0,1,0),0) AS Q7Valid, tblAssessment.Q8,
tblAssessment.Q9,
IIf([fldValid]=True,IIf([Q9]>0,1,0),0) AS Q9Valid, tblAssessment.Q10,
IIf([fldValid]=True,IIf([Q10]>0,1,0),0) AS Q10Valid, tblAssessment.Q11,
IIf([fldValid]=True,IIf([Q11]>0,1,0),0) AS Q11Valid, tblAssessment.Q12,
IIf([fldValid]=True,IIf([Q12]>0,1,0),0) AS Q12Valid, tblAssessment.Q13,
tblAssessment.Q14,
IIf([fldValid]=True,IIf([Q14]>0,1,0),0) AS Q14Valid, tblAssessment.Q15,
IIf([fldValid]=True,IIf([Q15]>0,1,0),0) AS Q15Valid, tblAssessment.Q16,
IIf([fldValid]=True,IIf([Q16]>0,1,0),0) AS Q16Valid, tblAssessment.Q17,
IIf([fldValid]=True,IIf([Q17]>0,1,0),0) AS Q17Valid, tblAssessment.Q18,
IIf([fldValid]=True,IIf([Q18]>0,1,0),0) AS Q18Valid, tblAssessment.Q19,
IIf([fldValid]=True,IIf([Q19]>0,1,0),0) AS Q19Valid, tblAssessment.Q20,
tblAssessment.Q21,
IIf([fldValid]=True,IIf([Q21]>0,1,0),0) AS Q21Valid, tblAssessment.Q22,
IIf([fldValid]=True,IIf([Q22]>0,1,0),0) AS Q22Valid, tblAssessment.Q23,
IIf([fldValid]=True,IIf([Q23]>0,1,0),0) AS Q23Valid, tblAssessment.Q24,
IIf([fldValid]=True,IIf([Q24]>0,1,0),0) AS Q24Valid, tblAssessment.Q25,
IIf([fldValid]=True,IIf([Q25]>0,1,0),0) AS Q25Valid, tblAssessment.Q26,
IIf([fldValid]=True,IIf([Q26]>0,1,0),0) AS Q26Valid, tblAssessment.Q27,
IIf([fldValid]=True,IIf([Q27]>0,1,0),0) AS Q27Valid, tblAssessment.Q28,
IIf([fldValid]=True,IIf([Q28]>0,1,0),0) AS Q28Valid, tblAssessment.Q29,
tblAssessment.Q30,
tblAssessment.Q31, tblAssessment.Q32
FROM ((tblDistrict
LEFT JOIN tblRegion ON tblDistrict.fldDRegID = tblRegion.fldRegID)
RIGHT JOIN (((tblATraining
LEFT JOIN tblCourses ON tblATraining.fldTCrsID = tblCourses.fldCrsID)
LEFT JOIN tblPersonnel ON tblATraining.fldTPID = tblPersonnel.fldPID)
LEFT JOIN tblLocations ON tblATraining.fldTLocAbr = tblLocations.fldLID) ON tblDistrict.fldDistAbr = tblATraining.fldTDistAbr)
LEFT JOIN tblAssessment ON tblATraining.fldTID = tblAssessment.fldTrngCID
WHERE (((tblAssessment.fldValid)=True)
AND ((tblATraining.fldTCrsID) Like [forms]![fdlgRptCriteria].[selCrsCd])
AND ((tblATraining.fldTDateStart) Between [forms]![fdlgRptCriteria].[seldate1] And [forms]![fdlgRptCriteria].[seldate2])
AND ((tblAssessment.fldTrngSID) Is Not Null));
【问题讨论】:
-
尝试使用代码块 - 它会保留您的格式。
-
我尽力把它格式化成一些可读的东西。我对连接顺序的明确性感到困惑(Access 是否会遵守您指定的确切方式还有待商榷),以及 WHERE 子句中的所有括号,但这没关系。
-
@lc: ACE/Jet 强制通过要求每个连接(最后一个连接除外)放在括号中来明确连接顺序。但是您是正确的,因为优化器可以在认为合适的情况下更改顺序,所以不能保证 JOIN 顺序(这是 ACE/Jet 不符合标准 SQL 的另一种方式)。
-
感谢大家对这个非常古老的问题的所有意见!对不起,我 7 年前没有说谢谢!