MS Access 等效查询

Question

我正在尝试编写一个我知道与 MySQL 到 MS Access 兼容的查询。这是一项编程作业，所以我不希望直接给我答案，但我不太了解 MS Access 的 SQL 版本。我自己编写了 MySQL，并对其进行了测试。那时我意识到查询需要为 MS Access 工作。所以这里是已知的代码：

SELECT `D`.`RENT_NUM`, 
    `R`.`RENT_DATE`, 
    `D`.`VID_NUM`, 
    `M`.`MOVIE_TITLE`, 
    `D`.`DETAIL_DUEDATE`, 
    `D`.`DETAIL_RETURNDATE`, 
    `D`.`DETAIL_FEE`, 
    `D`.`DETAIL_RETURNDATE` - `D`.`DETAIL_DUEDATE` AS `DAYS_LATE`
FROM `detailrental` AS `D`
    JOIN `rental` AS `R` ON `D`.`RENT_NUM` = `R`.`RENT_NUM`
    JOIN `video` AS `V` ON `D`.`VID_NUM` = `V`.`VID_NUM`
    JOIN `movie` AS `M` ON `V`.`MOVIE_NUM` = `M`.`MOVIE_NUM`
WHERE `D`.`DETAIL_RETURNDATE` - `D`.`DETAIL_DUEDATE` > 0
    ORDER BY `R`.`RENT_NUM`, `M`.`MOVIE_TITLE`;

我一直在尝试转换为 MS Access SQL，但还是不明白。这是最近的尝试。

SELECT [D].[RENT_NUM],
    [R].[RENT_DATE],
    [D].[VID_NUM],
    [M].[MOVIE_TITLE],
    [D].[DETAIL_DUEDATE],
    [D].[DETAIL_RETURNDATE],
    [D].[DETAIL_FEE],
    [D].[DETAIL_RETURNDATE] - [D].[DETAIL_DUEDATE] AS [DAYS_LATE]
FROM [DETAILRENTAL] AS [D] INNER JOIN 
( 
  [RENTAL] AS [R] INNER JOIN 
  (
    [VIDEO] AS [V] INNER JOIN [MOVIE] AS [M] ON [V].[MOVIE_NUM] = [M].[MOVIE_NUM]
  )  ON [D].[VID_NUM] = [V].[VID_NUM]
) ON [D].[RENT_NUM] = [R].[RENT_NUM]
WHERE [D].[DETAIL_RETURNDATE] - [D].[DETAIL_DUEDATE] > 0
    ORDER BY [R].[RENT_NUM], [M].[MOVIE_TITLE];

我收到的错误是 Syntax error in JOIN operation. 我知道那是什么意思，但我不知道 MS Access 的 SQL 足以发现错误。

Answer 1

自从我不得不编写任何访问查询以来已经有一段时间了，所以我只使用官方文档http://msdn.microsoft.com/en-us/library/office/bb208854(v=office.12).aspx 中描述的语法。发现它有语法错误。因此，要使查询工作，您必须用括号括起来 JOIN。但是每个ON 语句仍然需要在每组括号内而不是在外面。这应该可以解决问题。

SELECT [D].[RENT_NUM]
       ,[R].[RENT_DATE]
       ,[D].[VID_NUM]
       ,[M].[MOVIE_TITLE]
       ,[D].[DETAIL_DUEDATE]
       ,[D].[DETAIL_RETURNDATE]
       ,[D].[DETAIL_FEE]
       ,[D].[DETAIL_RETURNDATE] - [D].[DETAIL_DUEDATE] AS [DAYS_LATE]
    FROM (
           (
             (
               [detailrental] AS [D] )
             INNER JOIN [rental] AS [R]
                ON [D].[RENT_NUM] = [R].[RENT_NUM] )
           INNER JOIN [video] AS [V]
            ON D.VID_NUM = [V].[VID_NUM] )
    INNER JOIN [movie] AS [M]
        ON [V].[MOVIE_NUM] = [M].[MOVIE_NUM]
    WHERE [D].[DETAIL_RETURNDATE] - [D].[DETAIL_DUEDATE] > 0
    ORDER BY [R].[RENT_NUM]
       ,[M].[MOVIE_TITLE];

Answer 2

既然我们知道问题出在 JOIN 上，让我们从最里面的一组括号开始，然后向外工作：

[VIDEO] AS [V] 
INNER JOIN 
[MOVIE] AS [M] 
    ON [V].[MOVIE_NUM] = [M].[MOVIE_NUM]

看起来不错。让我们移出一层：

[RENTAL] AS [R] INNER JOIN 
(
    [VIDEO] AS [V] 
    INNER JOIN 
    [MOVIE] AS [M] 
        ON [V].[MOVIE_NUM] = [M].[MOVIE_NUM]
)
    ON [D].[VID_NUM] = [V].[VID_NUM]

此 JOIN 不起作用。你知道为什么吗？