【发布时间】:2016-06-13 18:26:23
【问题描述】:
以下查询是检索 (SGT_DISBURSEMENT_REQUEST) 计数仅为 1 的记录。它工作得很好。但在性能方面,因为我们有 100 000 条记录,所以并没有花费太多时间。
有没有更好的办法?
SELECT PA.PERSON_ID,
PA.PERSON_ACCOUNT_ID,
DR.DISBURSEMENT_REQUEST_ID,
SUM
(
ISNULL(CD.EE_PRE_TAX_AMT,0) +
ISNULL(CD.EE_ADDL_PRE_TAX_AMT,0)
) AS EE_PRE_TAX_CONTRIB,
DD.PRE_TAX_AMOUNT AS DISB_DTL_PRE_TAX_AMOUNT,
SUM
( ISNULL(CD.EE_POST_TAX_AMT,0) +
ISNULL(CD.EE_ADDL_POST_TAX_AMT,0)
) AS EE_POST_TAX_CONTRIB,
DD.POST_TAX_AMOUNT AS DISB_DTL_POST_TAX_AMOUNT
FROM SGT_DISBURSEMENT_REQUEST DR
INNER JOIN SGT_DISBURSEMENT_DETAIL DD ON DR.DISBURSEMENT_REQUEST_ID = DD.DISBURSEMENT_REQUEST_ID
INNER JOIN SGT_PERSON_ACCOUNT PA ON PA.PERSON_ACCOUNT_ID = DR.PERSON_ACCOUNT_ID
INNER JOIN SGT_CONTRIB_DTL CD ON CD.PERSON_ACCOUNT_ID = PA.PERSON_ACCOUNT_ID
WHERE DR.REQUEST_CATEGORY_VALUE = 'REFD' AND
DD.DETAIL_CATEGORY_VALUE = 'REFD' AND
CD.STATUS_VALUE = 'VALD' AND
CD.POSTED_DATE <= DR.ACCEPTED_TO_PAYROLL_DATE AND
DR.DISBURSEMENT_STATUS_VALUE <> 'CANL' AND
EXISTS
(
SELECT 1 FROM SGT_DISBURSEMENT_REQUEST SDR1
INNER JOIN SGT_DISBURSEMENT_DETAIL SDD1 ON SDD1.DISBURSEMENT_REQUEST_ID = SDR1.DISBURSEMENT_REQUEST_ID
WHERE SDR1.PERSON_ACCOUNT_ID = DR.PERSON_ACCOUNT_ID and SDD1.DETAIL_CATEGORY_VALUE = DD.DETAIL_CATEGORY_VALUE
GROUP BY SDR1.PERSON_ACCOUNT_ID
HAVING COUNT(*) = 1
)
GROUP BY
PA.PERSON_ID, PA.PERSON_ACCOUNT_ID, DR.DISBURSEMENT_REQUEST_ID, DD.PRE_TAX_AMOUNT, DD.POST_TAX_AMOUNT
【问题讨论】:
标签: sql sql-server-2008 sql-server-2005