每个月不同的多个月的数据（rs 总和）答案

【问题标题】：Data (sum of rs)for multiple months for each month diffrent每个月不同的多个月的数据（rs 总和）
【发布时间】：2016-03-03 09:14:56
【问题描述】：

我对sql真的很陌生

这是我的查询：

select rmname, sum(cast (PROPOSEDLIMIT as int)) as january
from los_ext 
where applicationdate between '01-01-2016' and '01-31-2016'
group by RMNAME

我希望每个月都在单个查询中使用此日期，而不总是使用日期 between function。

我该怎么做？

我希望我的输出为：

RMNAME   JAN   FEB   MARCH  APRIL   ....
Nitin    2222  3333  33333  34422   333

要取出所提出的限制的总和。

【问题讨论】：

您实际使用的是哪个RDBMS？ MySQL 或 SQL Server?
请添加一些示例数据

标签： mysql sql sql-server-2008

【解决方案1】：

尝试以下查询：

select 
    rmname, 
    sum(CASE WHEN MONTH(applicationDate) = 1 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as january,
    sum(CASE WHEN MONTH(applicationDate) = 2 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as February,
    sum(CASE WHEN MONTH(applicationDate) = 3 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as March,
    sum(CASE WHEN MONTH(applicationDate) = 4 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as April,
    sum(CASE WHEN MONTH(applicationDate) = 5 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as May,
    sum(CASE WHEN MONTH(applicationDate) = 6 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as June,
    sum(CASE WHEN MONTH(applicationDate) = 7 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as July,
    sum(CASE WHEN MONTH(applicationDate) = 8 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as August,
    sum(CASE WHEN MONTH(applicationDate) = 9 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as September,
    sum(CASE WHEN MONTH(applicationDate) = 10 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as October,
    sum(CASE WHEN MONTH(applicationDate) = 11 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as November,
    sum(CASE WHEN MONTH(applicationDate) = 12 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as December
    from los_ext 
    group by RMNAME,MONTH(applicationDate)

你可以在Pivot Table上收集一些知识。

注意：上述查询将汇总相同月份的数据，虽然月份可能属于不同年份。

For example 2015 February and 2014 February will be summed up to the same slot.

为了避免这种情况，您可以添加date range in where clause like you did。

因此，在 where 子句中添加该日期范围，查询将如下所示：

select 
    rmname, 
    sum(CASE WHEN MONTH(applicationDate) = 1 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as january,
    sum(CASE WHEN MONTH(applicationDate) = 2 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as February,
    sum(CASE WHEN MONTH(applicationDate) = 3 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as March,
    sum(CASE WHEN MONTH(applicationDate) = 4 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as April,
    sum(CASE WHEN MONTH(applicationDate) = 5 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as May,
    sum(CASE WHEN MONTH(applicationDate) = 6 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as June,
    sum(CASE WHEN MONTH(applicationDate) = 7 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as July,
    sum(CASE WHEN MONTH(applicationDate) = 8 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as August,
    sum(CASE WHEN MONTH(applicationDate) = 9 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as September,
    sum(CASE WHEN MONTH(applicationDate) = 10 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as October,
    sum(CASE WHEN MONTH(applicationDate) = 11 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as November,
    sum(CASE WHEN MONTH(applicationDate) = 12 THEN cast (PROPOSEDLIMIT as int) ELSE 0 END) as December
    from los_ext 
    WHERE applicationdate between '01-01-2016' and '31-12-2016'
    group by RMNAME,MONTH(applicationDate)

【讨论】：

【解决方案2】：

在派生表中执行 cast 和 month 内容（以节省一些输入，并符合 ANSI SQL。）：

select rmname,
       sum(case when mnth = 1 then proplim else 0 end) as jan,
       sum(case when mnth = 2 then proplim else 0 end) as feb,
       ...
       sum(case when mnth = 12 then proplim else 0 end) as dec
from
(
  select rmname, cast (PROPOSEDLIMIT as int) proplim, MONTH(applicationDate) mnth
  from los_ext 
  where applicationdate between '01-01-2016' and '01-31-2016'
) dt
group by RMNAME

【讨论】：