对 XML RAW 进行查询答案

【问题标题】：Making a query into a XML RAW对 XML RAW 进行查询
【发布时间】：2017-05-16 17:13:50
【问题描述】：

我正在使用事务 SQL，我得到了这些表...

main.locality - id,locality
main.job - id,jobs
main.person - name,surname,jobid,localityid,salary,gender

我需要得到这个输出 (XML RAW) PS。第一行是所有工作的平均工资第二行是所有女性的平均工资第三行是所有男性的平均工资第四行是那个职位和女性的平均工资第五行是该职位和男性的平均工资

<row Average="19827" /> 
<row gender="F" Average="19835" /> 
<row gender="M" Average="19819" /> 
<row job="C# Developer" Average="20941" /> 
<row job="C# Developer" gender="F" Average="20845" />
<row job="C# Developer" gender="M" Average="21027" />

有人可以帮我查询一下吗？

【问题讨论】：

标签： sql sql-server xml tsql aggregate

【解决方案1】：

我在想：

-- 1. SAMPLE DATA
DECLARE @locality TABLE (localityid int, locality int);
DECLARE @job TABLE (id int, Job varchar(100));
DECLARE @person TABLE 
(
  name varchar(100), 
  surname varchar(100),
  jobid int,
  localityid int,
  salary money,
  gender char(1)
);

INSERT @locality VALUES (1, 10), (2, 20), (3, 35), (4, 1000);
INSERT @job VALUES (1, 'C# Developer'), (2, 'DBA');
INSERT @person VALUES 
('joe', 'blow', 1, 1, 100000, 'M'),
('Sally', 'Doe', 1, 2, 135000, 'F'),
('Sue', 'Smith', 2, 2, 115000, 'F'),
('Kyle', 'Jones', 2, 3, 107500, 'M')
; 

-- 2. SOLUTION:
SELECT gender = NULL, job = NULL, average = AVG(p.salary)
FROM @person p
UNION ALL
SELECT p.gender, job = NULL, average = AVG(p.salary) 
FROM @person p
JOIN @job j ON p.jobid = j.id
GROUP BY p.gender
UNION ALL
SELECT gender = NULL, job = j.job, average = AVG(p.salary) 
FROM @person p
JOIN @job j ON p.jobid = j.id
GROUP BY j.Job
UNION ALL
SELECT p.gender, j.Job, average = AVG(p.salary)
FROM @person p
JOIN @job j ON p.jobid = j.id
GROUP BY p.gender, j.Job
FOR XML RAW;

<row average="114375.0000" />
<row gender="F" average="125000.0000" />
<row gender="M" average="103750.0000" />
<row job="C# Developer" average="117500.0000" />
<row job="DBA" average="111250.0000" />
<row gender="F" job="C# Developer" average="135000.0000" />
<row gender="M" job="C# Developer" average="100000.0000" />
<row gender="F" job="DBA" average="115000.0000" />
<row gender="M" job="DBA" average="107500.0000" />

【讨论】：

嗨，好方法，我这边+1（我借用了你的示例数据，谢谢）。我的回答显示了使用ROLLUP 的更简单的方法，您可能会感兴趣...
干得好 shnugo。我早该想到的。

【解决方案2】：

这是a job for ROLLUP

（我借用了 Alan Burstein 的样本数据 - 谢谢！）

-- 1. SAMPLE DATA
DECLARE @locality TABLE (localityid int, locality int);
DECLARE @job TABLE (id int, Job varchar(100));
DECLARE @person TABLE 
(
  name varchar(100), 
  surname varchar(100),
  jobid int,
  localityid int,
  salary money,
  gender char(1)
);

INSERT @locality VALUES (1, 10), (2, 20), (3, 35), (4, 1000);
INSERT @job VALUES (1, 'C# Developer'), (2, 'DBA');
INSERT @person VALUES 
('joe', 'blow', 1, 1, 100000, 'M'),
('Sally', 'Doe', 1, 2, 135000, 'F'),
('Sue', 'Smith', 2, 2, 115000, 'F'),
('Kyle', 'Jones', 2, 3, 107500, 'M');


SELECT j.Job
      ,p.gender 
      ,AVG(p.salary) AS Average 
FROM @person AS p
INNER JOIN @locality AS l ON p.localityid=l.localityid
INNER JOIN @job AS j ON p.jobid=j.id
GROUP BY ROLLUP (gender,job)
ORDER BY job,gender
FOR XML RAW

结果

<row Average="114375.0000" />
<row gender="F" Average="125000.0000" />
<row gender="M" Average="103750.0000" />
<row Job="C# Developer" gender="F" Average="135000.0000" />
<row Job="C# Developer" gender="M" Average="100000.0000" />
<row Job="DBA" gender="F" Average="115000.0000" />
<row Job="DBA" gender="M" Average="107500.0000" />

【讨论】：