sql 中的 xml 节点：如何强制结束 daugther 节点

Question

有没有办法在 sql 中强制结束 xml daugther 节点？我需要结束并重新打开一个特定的节点。我的代码目前看起来像：

USE [DBNAME]
Select (Select 
        'EK' as 'prices/price/group',
        XUVP as 'prices/price/price',
        '1'  as 'prices/price/from',
        'beliebig' as 'prices/price/to',
        'FH' as 'prices/price/group',
        XHEK as 'prices/price/price',
        '1'  as 'prices/price/from',
        'beliebig' as 'prices/price/to',
        'D' as 'prices/price/group',
        XDEK as 'prices/price/price',
        '1'  as 'prices/price/from',
        'beliebig' as 'prices/price/to',
        'P' as 'prices/price/group',
        XPEK as 'prices/price/price',
        '1'  as 'prices/price/from',
        'beliebig' as 'prices/price/to'             
        FOR XML Path('article'),Type,Elements)      
FROM [dbo].[TABLENAME] FOR XML PATH ('articles'), Elements, ROOT('Root')
GO

导致：

      <prices>
        <price>
          <group>EK</group>
          <price>459.000</price>
          <from>1</from>
          <to>beliebig</to>
  ---->   </price>
  ---->   <price> 
          <group>FH</group>
          <price>279.000</price>
          <from>1</from>
          <to>beliebig</to>            
        </price>
      </prices>

我需要在四个子注释之后“强制结束”每个价格层（第二层），并为四个节点的下一个开始一个新的价格层。缺少的结束和开始标签被添加并标记在上面发布的结果中。

此外，我想为任何语法错误道歉，但我不是本地人。即使这个问题对于习惯 sql 的人来说可能是一件容易的事情，但我真的很感谢您能帮上忙。

在此先感谢并致以最良好的祝愿

音

Answer 1

不确定这是否是您正在寻找的确切结果，但您可以通过插入 NULL 看到，标签将重置

Declare @YourTable table (XUVP int,XHEK int,XDEK int,XPEK int)
Insert Into @YourTable values
(459,279,-999,999)

Select (Select 
        'EK' as 'price/group',
        XUVP as 'price/price',
        '1'  as 'price/from',
        'beliebig' as 'price/to',
        null,
        'FH' as 'price/group',
        XHEK as 'price/price',
        '1'  as 'price/from',
        'beliebig' as 'price/to',
        null,
        'D' as 'price/group',
        XDEK as 'price/price',
        '1'  as 'price/from',
        'beliebig' as 'price/to',
        null,
        'P' as 'price/group',
        XPEK as 'price/price',
        '1'  as 'price/from',
        'beliebig' as 'price/to'             
        FOR XML Path('prices'),Type,Elements, ROOT('article'))      
FROM @YourTable FOR XML PATH ('articles'), Elements, ROOT('Root')

退货

<Root>
  <articles>
    <article>
      <prices>
        <price>
          <group>EK</group>
          <price>459</price>
          <from>1</from>
          <to>beliebig</to>
        </price>
        <price>
          <group>FH</group>
          <price>279</price>
          <from>1</from>
          <to>beliebig</to>
        </price>
        <price>
          <group>D</group>
          <price>-999</price>
          <from>1</from>
          <to>beliebig</to>
        </price>
        <price>
          <group>P</group>
          <price>999</price>
          <from>1</from>
          <to>beliebig</to>
        </price>
      </prices>
    </article>
  </articles>
</Root>