从 XML 文件插入

Question

我正在尝试使用 XML 文件更新客户表，但它没有将 XML 中的值提取到变量中以传递到表中。我得到的错误是“无法将值 NULL 插入到列 'EmailAddress' 中”，即使 EmailAddress 显然有一个值。我觉得我错过了一些非常简单的东西，但无法弄清楚。有什么想法吗？

USE MyGuitarShop

DECLARE @CustomerUpdate XML

SET @CustomerUpdate = 
    '<NewCustomers>
        <Customer EmailAddress="izzychan@yahoo.com" Password="" FirstName="Isabella" LastName="Chan" />
        <Customer EmailAddress="johnprine@gmail.com" Password="" FirstName="John" LastName="Prine" />
        <Customer EmailAddress="kathykitchen@sbcglobal.net" Password="" FirstName="Kathy" LastName="Kitchen" />
    </NewCustomers>';

INSERT Customers (EmailAddress, Password, FirstName, LastName)
    VALUES
    (
        @CustomerUpdate.value('(/NewCustomers/Customer/EmailAddress)[1]', 'varchar(255)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/Password)[1]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/FirstName)[1]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/LastName)[1]', 'varchar(60)')        
    );

SELECT * FROM Customers

Answer 1

我觉得我错过了一些非常简单的东西......

是的，你是对的 :-D，你缺少 @ 来读取 属性-值：

DECLARE @CustomerUpdate XML

SET @CustomerUpdate = 
    '<NewCustomers>
        <Customer EmailAddress="izzychan@yahoo.com" Password="" FirstName="Isabella" LastName="Chan" />
        <Customer EmailAddress="johnprine@gmail.com" Password="" FirstName="John" LastName="Prine" />
        <Customer EmailAddress="kathykitchen@sbcglobal.net" Password="" FirstName="Kathy" LastName="Kitchen" />
    </NewCustomers>';

SELECT
        @CustomerUpdate.value('(/NewCustomers/Customer/@EmailAddress)[1]', 'varchar(255)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@Password)[1]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@FirstName)[1]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@LastName)[1]', 'varchar(60)')        

更新：一次性插入所有 <Customer>

试试这个：

DECLARE @Customers TABLE(EMailAddress VARCHAR(100),[Password] VARCHAR(100),FirstName VARCHAR(100),LastName VARCHAR(100));

DECLARE @CustomerUpdate XML

SET @CustomerUpdate = 
    '<NewCustomers>
        <Customer EmailAddress="izzychan@yahoo.com" Password="" FirstName="Isabella" LastName="Chan" />
        <Customer EmailAddress="johnprine@gmail.com" Password="" FirstName="John" LastName="Prine" />
        <Customer EmailAddress="kathykitchen@sbcglobal.net" Password="" FirstName="Kathy" LastName="Kitchen" />
    </NewCustomers>';

INSERT INTO @Customers (EmailAddress, Password, FirstName, LastName)
SELECT c.value('@EmailAddress', 'varchar(255)')
      ,c.value('@Password', 'varchar(60)')
      ,c.value('@FirstName', 'varchar(60)')
      ,c.value('@LastName', 'varchar(60)')        
FROM @CustomerUpdate.nodes(N'/NewCustomers/Customer') AS A(c)

SELECT * FROM @Customers

Answer 2

此代码现在可以完美运行。

    USE MyGuitarShop

DECLARE @CustomerUpdate XML

SET @CustomerUpdate = 
    '<NewCustomers>
        <Customer EmailAddress="izzychan@yahoo.com" Password="" FirstName="Isabella" LastName="Chan" />
        <Customer EmailAddress="johnprine@gmail.com" Password="" FirstName="John" LastName="Prine" />
        <Customer EmailAddress="kathykitchen@sbcglobal.net" Password="" FirstName="Kathy" LastName="Kitchen" />
    </NewCustomers>';

INSERT Customers (EmailAddress, Password, FirstName, LastName)
    VALUES
    (
        @CustomerUpdate.value('(/NewCustomers/Customer/@EmailAddress)[1]', 'varchar(255)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@Password)[1]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@FirstName)[1]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@LastName)[1]', 'varchar(60)')       
    );

INSERT Customers (EmailAddress, Password, FirstName, LastName)
    VALUES
    (
        @CustomerUpdate.value('(/NewCustomers/Customer/@EmailAddress)[2]', 'varchar(255)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@Password)[2]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@FirstName)[2]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@LastName)[2]', 'varchar(60)')       
    );

INSERT Customers (EmailAddress, Password, FirstName, LastName)
    VALUES
    (
        @CustomerUpdate.value('(/NewCustomers/Customer/@EmailAddress)[3]', 'varchar(255)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@Password)[3]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@FirstName)[3]', 'varchar(60)'),
        @CustomerUpdate.value('(/NewCustomers/Customer/@LastName)[3]', 'varchar(60)')       
    );

SELECT * FROM Customers