【发布时间】:2019-04-18 09:46:08
【问题描述】:
我正在尝试使用 UI 连接两个表,但其中一个表中的 UI 前面有“CLIENT_”。当尝试从字符串中删除“CLIENT_”然后比较 UI 时,我收到以下错误。
将数据类型 nvarchar 转换为浮点数时出错。
当尝试将整个子查询转换或强制转换为 INT 或 FLOAT 时,会发生相同的错误。
有没有人有任何想法或知道我如何编写代码以使其正常工作。
SELECT DISTINCT 69 AS 'FIELD_ID',
ENTITY_ID,
AD.WIP AS 'WIP'
FROM [WORKVIEW].[DBO].ENTITY_MASTER EM
JOIN [LIVE].[MHGROUP].PROJECTS P ON P.PRJ_ID = EM.ENTITY_PARENT
JOIN [WORKVIEW].[DBO].adn_NAMEACCOUNTSDATA_STAGING AD ON
CAST((SELECT SUBSTRING(P.CUSTOM1, CHARINDEX ('_', P1.CUSTOM1) -1, LEN(P1.CUSTOM1))
FROM [IMAN-SQL].[LIVE].[MHGROUP].PROJECTS P1
WHERE P.CUSTOM1 LIKE 'CLIENT_%') AS INT) = AD.NAMENO
我希望能够加入 P.CUSTOM1 和 AD.NAMENO 上的 NAMEACCOUNTSDATA_STAGING,因为这些是我可以将这些表加入在一起的唯一字段。
这项工作的最新尝试....
SELECT DISTINCT 69 AS 'FIELD_ID',
ENTITY_ID,
AD.WIP AS 'WIP'
FROM [WORKVIEW].[DBO].ENTITY_MASTER EM
JOIN [IMAN-SQL].[LIVE].[MHGROUP].PROJECTS P ON P.PRJ_ID = EM.ENTITY_PARENT
JOIN [WORKVIEW].[DBO].WORKVIEW_NAMEACCOUNTSDATA_STAGING AD ON CONCAT('CLIENT_', AD.NAMENO) = P.CUSTOM1 AND P.CUSTOM1 LIKE 'CLIENT_%'
涉及的所有三个表的架构:
TABLE [dbo].[entity_master](
[entity_id] [int] IDENTITY(1,1) NOT NULL,
[entity_parent] [nvarchar](50) NOT NULL,
[entity_child] [nvarchar](50) NOT NULL,
[entity_status] [int] NOT NULL,
[entity_child_name] [nvarchar](250) NULL,
[entity_parent_name] [nvarchar](250) NULL,
[GUID] [varchar](50) NULL,
TABLE [dbo].[WORKVIEW_NAMEACCOUNTSDATA_STAGING](
[NAMENO] [int] NOT NULL,
[WIP] [decimal](18, 2) NULL,
[BILLED] [decimal](18, 2) NULL,
[WRITTENOFF] [decimal](18, 2) NULL,
[DEBTORRESTRICTION] [nvarchar](max) NULL,
[PAYMENTTERMS] [int] NULL,
[BILLING FREQUENCY] [nvarchar](max) NULL
TABLE [MHGROUP].[PROJECTS](
[PRJ_ID] [float] NOT NULL,
[PRJ_PID] [float] NULL,
[DEFAULT_SECURITY] [char](1) NOT NULL,
[IS_SECURED] [char](1) NOT NULL,
[PRJ_NAME] [nvarchar](254) NULL,
[PRJ_OWNER] [nvarchar](64) NULL,
[PRJ_DESCRIPT] [nvarchar](254) NULL,
[PRJ_STATE] [char](1) NULL,
[PRJ_PUBLIC] [char](1) NULL,
[PRJ_LOCATION] [nvarchar](254) NULL,
[TYPE] [int] NOT NULL,
[SUBTYPE] [nvarchar](64) NULL,
[INHERITS_SECURITY] [char](1) NOT NULL,
[DOCNUM] [float] NULL,
[VERSION] [int] NULL,
[CUSTOM1] [nvarchar](254) NULL,
[CUSTOM2] [nvarchar](254) NULL,
[CUSTOM3] [nvarchar](254) NULL,
[LEFT_VISIT] [int] NULL,
[RIGHT_VISIT] [int] NULL,
[TREE_ID] [int] NULL,
[EMAIL] [nvarchar](254) NULL,
[DOC_SAVED_SEARCH] [int] NULL,
[LAYOUT_NAME] [nvarchar](254) NULL,
[LAYOUT_ORDER] [int] NULL,
[LAYOUT_VIEW] [nvarchar](max) NULL,
[REFERENCE_DATABASE] [nvarchar](32) NULL,
[REFERENCE_PRJ_ID] [float] NULL,
[REFERENCE_TYPE] [int] NULL,
[REFERENCE_SUBTYPE] [nvarchar](64) NULL,
[IS_EXTERNAL] [char](1) NOT NULL,
[EXTRNL_AS_NRML] [char](1) NOT NULL,
[IS_DOC_SVD_SRCH] [char](1) NOT NULL,
[IS_PRJ_SVD_SRCH] [char](1) NOT NULL,
[IS_HIDDEN] [char](1) NOT NULL,
[EDITWHEN] [datetime] NOT NULL,
希望这就是您想要的。
【问题讨论】:
-
AD.NAMENO 绝对是 INT 列吗?请发布一些使用其数据类型的表的详细信息(或至少用于连接的列)
-
哦 - 还要标记您正在使用哪种 SQL 风格(例如 TSQL、MySQL、Postgre 等)
-
嗨 iainc,感谢您的回复。我已经包括了你的要求。希望这对您有所帮助。
标签: sql tsql join substring charindex