sql - 如何将全名拆分为名字和姓氏

Question

如果我有一个包含全名的列的表，例如：

fullname
------------
Joe Bloggs
Peter Smith
Mary Jones and Liz Stone

如何使用 SQL 重试全名列中每个条目的名字和姓氏。在我的示例中，我并不担心第三个条目中的第二个名字，即 Liz Stone。

所以基本上是检索

Firstname
---------
Joe
Peter
Mary

Lastname  
--------
Bloggs 
Smith
Jones

Answer 1

这是一个 SQL Server 2016 之前的方法，它使用基本的字符串函数来隔离名字和姓氏。

SELECT SUBSTRING(fullname, 1, CHARINDEX(' ', fullname) - 1) AS Firstname,     
       SUBSTRING(fullname,
                 CHARINDEX(' ', fullname) + 1,
                 LEN(fullname) - CHARINDEX(' ', fullname)) AS Lastname
FROM yourTable

请注意，此解决方案假定 fullname 列仅包含一个名字和一个姓氏（即没有中间名、首字母等）。

Answer 2

这是一个滑坡，没有简单的答案。也就是说，请考虑以下内容

Declare @YourTable table (FullName varchar(50))
Insert Into @YourTable values
('Joe Bloggs'),
('Peter Smith'),
('Betty Jane Martinez'),
('Mary Jones and Liz Stone')


Select A.*
      ,FirstName = Pos1+case when Pos3 is not null then ' '+Pos2 else '' end
      ,LastName  = case when Pos3 is null then Pos2 else Pos3 end
 From @YourTable A
 Cross Apply (
    Select Pos1 = xDim.value('/x[1]','varchar(max)')
          ,Pos2 = xDim.value('/x[2]','varchar(max)')
          ,Pos3 = xDim.value('/x[3]','varchar(max)')
          ,Pos4 = xDim.value('/x[4]','varchar(max)')
          ,Pos5 = xDim.value('/x[5]','varchar(max)')
          ,Pos6 = xDim.value('/x[6]','varchar(max)')
     From  (Select Cast('<x>' + replace((Select substring(FullName,1,charindex(' and ',FullName+' and ')-1) as [*] For XML Path('')),' ','</x><x>')+'</x>' as xml) as xDim) as A 
 ) B

返回

FullName                    FirstName   LastName
Joe Bloggs                  Joe         Bloggs
Peter Smith                 Peter       Smith
Betty Jane Martinez         Betty Jane  Martinez
Mary Jones and Liz Stone    Mary        Jones

如果对视觉有帮助，则 CROSS APPLY 生成

Answer 3

SELECT CASE
           WHEN CHARINDEX(' ', FullName) > 0
           THEN SUBSTRING(FullName, 1, LEN(FullName) - CHARINDEX(' ', REVERSE(FullName)))
           ELSE ''
       END AS FirstName,
       CASE
           WHEN CHARINDEX(' ', FullName) > 0
           THEN REVERSE(SUBSTRING(REVERSE(FullName), 
                       1, 
                       CHARINDEX(' ', REVERSE(FullName)) - 1))
           ELSE FullName
       END AS LastName
FROM(VALUES('Mary Anne Bloggs'), ('Joe Bloggs'), ('Bloggs')) AS T(FullName);

此版本检查全名中是否有空格进行拆分。如果没有，则将名字设置为空字符串，并将全名放入姓氏中。另外，如果有多个空格，则在最后一个空格上使用 reverse 进行拆分

Answer 4

BigQuery：标准 Sql

substr(name,1,STRPOS(name,' ')-1) as FirstName,

substr(name,STRPOS(name,' ')+1,length(name)) as LastName

Answer 5

我使用这个查询来检索名字和姓氏

SELECT SUBSTRING(FULLNAME, 1, CASE WHEN CHARINDEX(' ', FULLNAME)>0 THEN CHARINDEX(' ', FULLNAME) - 1 ELSE LEN(FULLNAME) END ) AS Firstname,
  REVERSE(SUBSTRING(REVERSE(FULLNAME), 1, CASE WHEN CHARINDEX(' ', REVERSE(FULLNAME))>0 THEN CHARINDEX(' ', REVERSE(FULLNAME)) - 1 ELSE LEN(REVERSE(FULLNAME)) END ) )AS Firstname FROM  HRMDESFO.EMPLOID

Resuls

Answer 6

在没有任何假设的情况下，这是这个问题的最简单和最短的。您还可以使用rtrim(ltrim('firstname lastname')) 进一步增强此功能。

以防字符串前有空格，

Select 
    substring('Firstname Lastname',1,CHARINDEX(' ', 'Firstname Lastname')) as firstname, 
    substring('Firstname Lastname',CHARINDEX(' ', 'Firstname Lastname'),LEN('Firstname Lastname')) as Lastname

Answer 7

select  passemail,substring(passemail,1,instr(passemail,'@') - 1) as name ,
substring(passemail,instr(passemail,'@') + 1,length(passemail)) from passenger

Answer 8

获取名字

SELECT SUBSTR(FULLNAME,1,(LOCATE(' ',FULLNAME)))  AS FIRSTTNAME from EmployeeDetails;

为姓氏

SELECT SUBSTR(FULLNAME,(LOCATE(' ',FULLNAME)))  AS LASTNAME from EmployeeDetails;

所以

SELECT  SUBSTR(FULLNAME,1,(LOCATE(' ',FULLNAME)))  AS FIRSTTNAME, SUBSTR(FULLNAME,(LOCATE(' ',FULLNAME)))  AS LASTNAME from EmployeeDetails;

Answer 9

SELECT 
  LEFT(column_name,  POSITION(' ' IN column_name)-1)                     AS first_name,
  RIGHT(column_name, LENGTH(column_name) - POSITION(' ' IN column_name)) AS last_name
FROM table_name

Answer 10

SELECT SUBSTR(NAME,1,(LOCATE(NAME, ' '))) AS FIRSTTNAME, SUBSTR(NAME,(LOCATE(NAME, ' ')+1)) AS LASTNAME from yourTABLE;

Answer 11

你可以使用，

 STRING_SPLIT (string , separator)