合并开始日期和结束日期循环日期答案

【问题标题】：merging start and end date cycle dates合并开始日期和结束日期循环日期
【发布时间】：2020-02-12 18:20:44
【问题描述】：

我有下表。

CUST_ID START_CYCLE END_CYCLE   WORKER  CUST_SUB_ID CUST_SUB_TYPE
101     1/1/2019    1/31/2019   ABC123  134         HIGH_SUB
101     2/1/2019    4/30/2019   ABC123  136         HIGH_SUB
101     5/1/2019    7/31/2019   ABC123  1414        HIGH_SUB
101     8/1/2019    8/30/2019   ABC123  1469        HIGH_SUB

发生以下情况时，我需要合并日期（不包括行）。

标准：

leadcust_sub_id <>cust_sub_id

leadcust_sub_type = cust_sub_type

leadcust_id = cust_id

leadworker = worker

最终输出：

CUST_ID START_CYCLE END_CYCLE   WORKER  CUST_SUB_ID         CUST_SUB_TYPE
 101    1/1/2019    8/30/2019   ABC123  134:136:1414:1469   HIGH_SUB

SQL：

select 
cust_id,
start_cycle,
end_cycle,
worker,
cust_sub_id,
cust_sub_type,
gaps_in_srv,
case
when gaps_in_srv = 'N'
and cust_sub_id <> lead(cust_sub_id) over (partition by cust_id order by start_cycle) 
and cust_id = lead(cust_id) over (partition by cust_id order by start_cycle)
and worker = lead(worker) over (partition by cust_id order by start_cycle)
then 'Y'
else 'N'
end merge_dts,
dense_rank() over (partition by cust_id, cust_sub_id order by start_cycle) rnk_fst_dt,
dense_rank() over (partition by cust_id, cust_sub_id order by start_cycle desc) rnk_lst_dt
from cust_cycle

我可以在删除行后使用listagg 捕获 cust_sub_id，但在应用 listagg 函数之前需要帮助删除这些行。

【问题讨论】：

标签： sql oracle listagg lead

【解决方案1】：

您可以使用lag() 来确定“孤岛”的起始位置和累积总和以将分组编号分配给孤岛：

select cust_id, worker, cust_sub_type, min(start_cycle), max(end_cycle),
       listagg(cust_sub_id, ':') within group (order by start_cycle) as cust_sub_ids
from (select cc.*,
             sum(case when prev_ec <> start_cycle - interval '1' day or
                           prev_cst <> cust_sub_type
                      then 1 else 0
                 end) over (partition by cust_id, worker order by start_cycle) as grp
      from (select cc.*,
                   lag(end_cycle) over (partition by cust_id, worker order by start_cycle) as prev_ec,
                   lag(cust_sub_type) over (partition by cust_id, worker order by start_cycle) as prev_cst
            from cust_cycle cc
           ) cc
      ) cc
group by cust_id, worker, cust_sub_type, worker

【讨论】：